One model for a water molecule is to have a point charge of magnitude −2𝑒− at point (𝑥, 𝑦, 𝑧) = (0, 0, −𝑑/2) and two point charges of magnitude +𝑒− at points (±𝑑/4, 0, 𝑑/2). Verify that far from the molecule the fields for this model give a dipole distribution. How far away (relative to 𝑑) does the observation need to be for this to be true? 

To verify that the far-field distribution of the water molecule model corresponds to a dipole distribution, let's consider the arrangement of charges and calculate the dipole moment. Then, we'll determine the condition under which the far-field electric field resembles that of a dipole.

### Step 1: Calculate the Dipole Moment

The water molecule model consists of three point charges:
- A negative charge of \(-2e\) at \((0, 0, -d/2)\).
- Two positive charges of \(+e\) at \((d/4, 0, d/2)\) and \((-d/4, 0, d/2)\).

The electric dipole moment \(\mathbf{p}\) is defined as:

\[
\mathbf{p} = \sum_i q_i \mathbf{r}_i
\]

where \(q_i\) is the charge and \(\mathbf{r}_i\) is its position vector.

For this system:
- Negative charge contribution: 
  \[
  \mathbf{p}_\text{neg} = -2e \cdot (0, 0, -d/2) = (0, 0, ed)
  \]
- Positive charge contribution (since the two charges are symmetric and only contribute along the z-axis):
  \[
  \mathbf{p}_\text{pos} = e \cdot \left(\frac{d}{4}, 0, \frac{d}{2}\right) + e \cdot \left(-\frac{d}{4}, 0, \frac{d}{2}\right) = (0, 0, ed)
  \]

Thus, the total dipole moment is:

\[
\mathbf{p} = (0, 0, ed) + (0, 0, ed) = (0, 0, 2ed)
\]

### Step 2: Far-Field Condition for Dipole Distribution

In the far-field region, the distance \(r\) from the dipole to the observation point should be much larger than the separation between the charges \(d\). For the far-field approximation to hold, the distance \(r\) must satisfy:

\[
r \gg d
\]

This ensures that the electric field behaves like that of a pure dipole, which falls off as \(1/r^3\) rather than the individual fields of the point charges.

### Conclusion

To observe a dipole distribution, the observation point needs to be at a distance \(r\) from the molecule such that \(r\) is significantly larger than the separation distance \(d\). Typically, this is interpreted as \(r \geq 10d\) to ensure the dominance of the dipole term in the field.

Would you like more details or have any questions?

### Related Questions:
1. How does the field of a dipole differ from that of a monopole?
2. How is the potential field calculated for a dipole at far distances?
3. What is the significance of the dipole moment in molecular physics?
4. How would the electric field behave if the charges were not symmetrically placed?
5. What are real-world applications of understanding dipole fields?

### Tip:
When dealing with multipole expansions, remember that higher-order terms become negligible faster as the distance from the source increases.

Explore how the electric fields of a water molecule model exhibit dipole distribution in the far-field. Understand the calculations of dipole moment and the conditions required for observing dipole behavior in electric fields.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation