Math Problem Statement

Recall that, in a flow problem, if the flow pattern is described by an analytic function w=ϕ+iψ , then w is called the complex potential, ϕ the velocity potential and ψ the stream function.

Now in a flow problem if the stream function is given by ψ=x2−y2 , what will be its velocity potential ?

[Hint: Guessing the complex potential may help, but one can do it otherwise]

Question 3Answer

a. 2xy

b. 2ixy

c. −2xy

d. −2ixy

Solution

Given that the stream function is provided as ψ=x2y2\psi = x^2 - y^2, we want to find the corresponding velocity potential ϕ\phi, or the real part of the complex potential w=ϕ+iψw = \phi + i\psi.

Steps to Find the Velocity Potential:

  1. Complex potential definition: The complex potential w=ϕ+iψw = \phi + i\psi, where ϕ\phi is the velocity potential and ψ\psi is the stream function.

  2. Cauchy-Riemann equations: Since w=ϕ+iψw = \phi + i\psi is analytic, it must satisfy the Cauchy-Riemann equations: ϕx=ψy,ϕy=ψx\frac{\partial \phi}{\partial x} = \frac{\partial \psi}{\partial y}, \quad \frac{\partial \phi}{\partial y} = -\frac{\partial \psi}{\partial x}

  3. Given stream function: ψ=x2y2\psi = x^2 - y^2

  4. First Cauchy-Riemann equation: ϕx=ψy\frac{\partial \phi}{\partial x} = \frac{\partial \psi}{\partial y} Calculating ψy\frac{\partial \psi}{\partial y}: ψy=y(x2y2)=2y\frac{\partial \psi}{\partial y} = \frac{\partial}{\partial y}(x^2 - y^2) = -2y Therefore, ϕx=2y\frac{\partial \phi}{\partial x} = -2y

  5. Second Cauchy-Riemann equation: ϕy=ψx\frac{\partial \phi}{\partial y} = -\frac{\partial \psi}{\partial x} Calculating ψx\frac{\partial \psi}{\partial x}: ψx=x(x2y2)=2x\frac{\partial \psi}{\partial x} = \frac{\partial}{\partial x}(x^2 - y^2) = 2x Therefore, ϕy=2x\frac{\partial \phi}{\partial y} = -2x

  6. Solving for ϕ\phi: Integrating both partial derivatives, we obtain ϕ\phi.

    • From ϕx=2y\frac{\partial \phi}{\partial x} = -2y, integrate with respect to xx: ϕ(x,y)=2xy+f(y)\phi(x, y) = -2xy + f(y)
    • From ϕy=2x\frac{\partial \phi}{\partial y} = -2x, integrate with respect to yy: ϕ(x,y)=2xy+g(x)\phi(x, y) = -2xy + g(x)

    Since the function of integration f(y)f(y) or g(x)g(x) must be a constant, the velocity potential is: ϕ(x,y)=2xy\phi(x, y) = -2xy

Thus, the correct answer is:

Option (c): 2xy-2xy


Would you like further details on any of the steps, or have any other questions?

Here are 5 related questions to explore further:

  1. How are the Cauchy-Riemann equations used in fluid flow problems?
  2. What is the physical significance of the velocity potential ϕ\phi?
  3. How can one derive the streamlines from the stream function?
  4. What conditions must a complex potential ww satisfy to describe a flow?
  5. Can the method of complex potential be applied to non-laminar flows?

Tip: In flow problems, the Cauchy-Riemann equations ensure that the velocity field satisfies continuity, implying an incompressible flow.

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Math Problem Analysis

Mathematical Concepts

Complex Potential
Velocity Potential
Stream Function
Cauchy-Riemann Equations

Formulas

w = ϕ + iψ (Complex Potential)
Cauchy-Riemann equations: ∂ϕ/∂x = ∂ψ/∂y, ∂ϕ/∂y = -∂ψ/∂x

Theorems

Cauchy-Riemann Theorem
Analytic Function Theorem

Suitable Grade Level

College-level (Undergraduate Fluid Dynamics or Complex Analysis)