Math Problem Statement

A random sample of 10 subjects have weights with a standard deviation of 12.4397 kg. What is the variance of their​ weights? Be sure to include the appropriate units with the result. Question content area bottom Part 1 The variance of the sample data is select: 154.6767 154.6767 kg squared . ​(Round to four decimal places as​ needed.)

Solution

To calculate the variance of the weights, we use the relationship between standard deviation and variance. The variance (σ2\sigma^2) is simply the square of the standard deviation (σ\sigma).

Given:

  • Standard deviation σ=12.4397\sigma = 12.4397 kg

The variance is: Variance=σ2=(12.4397)2\text{Variance} = \sigma^2 = (12.4397)^2

Now, let's compute that:

Variance=154.6767kg2\text{Variance} = 154.6767 \, \text{kg}^2

Thus, the variance of the sample data is 154.6767kg2154.6767 \, \text{kg}^2, rounded to four decimal places.

Would you like more details on how variance and standard deviation are related or need further clarification?

Here are 5 related questions you might find helpful:

  1. What is the formula for variance and how does it differ from standard deviation?
  2. How does sample size affect variance and standard deviation?
  3. What are some real-world examples where understanding variance is useful?
  4. How do you interpret variance in the context of weight data?
  5. Can you explain the difference between population variance and sample variance?

Tip: Always double-check whether you're working with a sample or population, as the formulas for variance slightly differ.

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Math Problem Analysis

Mathematical Concepts

Statistics
Variance
Standard Deviation

Formulas

Variance = (Standard Deviation)^2

Theorems

Relationship between Variance and Standard Deviation

Suitable Grade Level

Grades 10-12