To solve the expression \( \frac{18000 \, \text{mg}}{1 \, \text{mL}} \times \frac{1000 \, \text{mL}}{1 \, \text{g}} \), let's follow the steps systematically:

1. Multiply the numerators:  
   \( 18000 \, \text{mg} \times 1000 \, \text{mL} = 18,000,000 \, \text{mg} \cdot \text{mL} \)

2. Multiply the denominators:  
   \( 1 \, \text{mL} \times 1 \, \text{g} = 1 \, \text{mL} \cdot \text{g} \)

3. Divide the result:  
   \( \frac{18,000,000 \, \text{mg} \cdot \text{mL}}{1 \, \text{mL} \cdot \text{g}} = 18,000,000 \, \text{mg/g} \)

Since \( 1000 \, \text{mg} = 1 \, \text{g} \), we can convert \( 18,000,000 \, \text{mg/g} \) to grams:

\[
\frac{18,000,000 \, \text{mg}}{1000 \, \text{mg/g}} = 18,000 \, \text{g}
\]

Thus, the final result is \( 18,000 \, \text{g} \).

Do you want more details, or do you have any questions?

Here are 5 related questions to expand on this:

1. What are the units for the concentration of a solution?
2. How do you convert between milligrams and grams?
3. What is the significance of dimensional analysis in unit conversions?
4. Can you solve a similar problem with different units (e.g., liters, kilograms)?
5. How do you handle unit cancellations in complex expressions?

**Tip:** Always make sure that units cancel out properly in conversions to avoid errors in calculations.

Solve the unit conversion problem 18000mg/1mL × 1000mL/1g with a step-by-step guide. This example involves dimensional analysis and conversion between milligrams and grams, suitable for students in Grades 9-11.

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