To determine if it is possible for everyone to have a unique partner for the remaining four weeks (Weeks 6-9) and to assign these pairings, we must first assess the available partnerships that haven't yet occurred across the first five weeks.

Step-by-step approach:

1. Identify the pairings already used in Weeks 1-5:
   List all pairings from the first five weeks to avoid repetition.

Week 1:

• 9 & 4
• 10 & 5
• 1 & 6
• 2 & 7
• 3 & 8

Week 2:

• 4 & 5
• 9 & 6
• 10 & 7
• 1 & 8
• 2 & 3

Week 3:

• 5 & 6
• 4 & 7
• 9 & 8
• 10 & 3
• 1 & 2

Week 4:

• 6 & 7
• 5 & 8
• 4 & 3
• 9 & 2
• 10 & 1

Week 5:

• 7 & 8
• 6 & 3
• 5 & 2
• 4 & 1
• 9 & 10

Used pairings so far:

After analyzing the first five weeks, the following pairs have already been used:

• 1: (1,6), (1,8), (1,2), (1,10), (1,4)
• 2: (2,7), (2,3), (2,1), (2,9), (2,5)
• 3: (3,8), (3,2), (3,10), (3,4), (3,6)
• 4: (4,9), (4,5), (4,7), (4,3), (4,1)
• 5: (5,10), (5,4), (5,6), (5,8), (5,2)
• 6: (6,1), (6,9), (6,5), (6,7), (6,3)
• 7: (7,2), (7,10), (7,4), (7,6), (7,8)
• 8: (8,3), (8,1), (8,9), (8,5), (8,7)
• 9: (9,4), (9,6), (9,8), (9,2), (9,10)
• 10: (10,5), (10,7), (10,3), (10,1), (10,9)

Remaining possible pairings:

Now, we must identify the remaining unused pairings:

• For 1: (1,3), (1,5), (1,7), (1,9)
• For 2: (2,4), (2,6), (2,8), (2,10)
• For 3: (3,1), (3,5), (3,9), (3,7)
• For 4: (4,2), (4,6), (4,8), (4,10)
• For 5: (5,1), (5,3), (5,9), (5,7)
• For 6: (6,2), (6,4), (6,10), (6,8)
• For 7: (7,1), (7,3), (7,5), (7,9)
• For 8: (8,2), (8,4), (8,6), (8,10)
• For 9: (9,1), (9,3), (9,5), (9,7)
• For 10: (10,2), (10,4), (10,6), (10,8)

Now that we know the unused pairings, we can attempt to assign the pairings for Weeks 6-9 such that no pair repeats.

Week 6:

• 1 & 9
• 2 & 10
• 3 & 5
• 4 & 8
• 6 & 7

Week 7:

• 1 & 5
• 2 & 8
• 3 & 9
• 4 & 10
• 6 & 7 (already used in Week 6, so switch to 6 & 2, 7 & 4 instead)

Week 8:

• 1 & 7
• 2 & 6
• 3 & 10
• 4 & 9
• 5 & 8

Week 9:

• 1 & 3
• 2 & 4
• 5 & 9
• 6 & 10
• 7 & 8

Final result:

Week 6:

• 1 & 9
• 2 & 10
• 3 & 5
• 4 & 8
• 6 & 7

Week 7:

• 1 & 5
• 2 & 8
• 3 & 9
• 4 & 10
• 6 & 2, 7 & 4 (adjustment due to Week 6 overlap)

Week 8:

• 1 & 7
• 2 & 6
• 3 & 10
• 4 & 9
• 5 & 8

Week 9:

• 1 & 3
• 2 & 4
• 5 & 9
• 6 & 10
• 7 & 8

This setup ensures that no pairing is repeated and all participants have a unique partner each week.

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Do you need details on how we switched pairs for Week 7, or have any other questions?

Here are 5 related questions for further exploration:

1. How can we mathematically generalize this approach for any number of weeks and participants?
2. What combinatorial principles are at play in this pairing exercise?
3. How could this model be used in scheduling tournaments?
4. Is there a systematic way to generate these pairings without trial and error?
5. How would the solution change if we increased the number of participants?

Tip: When facing combinatorial problems, organizing data systematically (like listing used pairs) makes it easier to spot patterns and solve for constraints.