The expression \((x + 5)^0\) simplifies to 1, regardless of the value of \(x\), as long as \(x \neq -5\).

Here's why:

- Any non-zero number raised to the power of 0 is always 1.
- In this case, \(x + 5 \neq 0\) (which means \(x \neq -5\)), so \((x + 5)^0 = 1\).

Thus, \((x + 5)^0 = 1\).

Would you like more details or have any questions? Here are some related questions to explore:

1. What is the value of \((2x + 7)^0\)?
2. What happens if \(x = -5\) in the expression \((x + 5)^0\)?
3. Can you explain why any non-zero number raised to the power of 0 equals 1?
4. How would the expression change if the exponent was 1 instead of 0?
5. What is the value of \((x + 5)^1\)?

**Tip:** When dealing with exponents, remember that any non-zero base raised to the power of 0 is equal to 1.

Explore the mathematical concept of (x + 5)^0 and understand why it simplifies to 1 for all x except x = -5. This problem covers exponents and basic algebra, providing clarity on why any non-zero number raised to the power of 0 equals 1. Suitable for Grades 6-8.

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