Math Problem Statement

your wrong you forgot that they are mathematically similar

Solution

You're correct to point that out; let's revisit the problem with the correct approach, keeping in mind that the cylinders are mathematically similar.

Understanding Mathematical Similarity:

When two shapes are mathematically similar, the ratio of corresponding linear dimensions (like radii and heights) is the same, and the ratio of their areas is the square of the ratio of their linear dimensions. For volumes, the ratio is the cube of the linear dimension ratio.

Correct Solution:

  1. Given Information:

    • Cylinder A: Radius rA=3cmr_A = 3 \, \text{cm} (from cross-sectional area 18cm2=πrA218 \, \text{cm}^2 = \pi r_A^2).
    • Height of Cylinder A: hA=5cmh_A = 5 \, \text{cm}.
    • Height of Cylinder B: hB=10cmh_B = 10 \, \text{cm}.
  2. Determine the Ratio of Heights (which equals the Ratio of Radii):

    • hBhA=10cm5cm=2\frac{h_B}{h_A} = \frac{10 \, \text{cm}}{5 \, \text{cm}} = 2.

    This means that the ratio of the radii rBrA\frac{r_B}{r_A} is also 22.

  3. Calculate the Radius of Cylinder B:

    • rB=2×rA=2×3cm=6cmr_B = 2 \times r_A = 2 \times 3 \, \text{cm} = 6 \, \text{cm}.
  4. Calculate the Volume of Cylinder B: The volume of a cylinder is given by: V=πr2hV = \pi r^2 h So, the volume of Cylinder B: VB=π×(6cm)2×10cm=π×36cm2×10cm=360πcm3V_B = \pi \times (6 \, \text{cm})^2 \times 10 \, \text{cm} = \pi \times 36 \, \text{cm}^2 \times 10 \, \text{cm} = 360\pi \, \text{cm}^3

  5. Final Volume Calculation: Since the linear dimensions scale by a factor of 2, the volume scales by a factor of 23=82^3 = 8.

    • The volume of Cylinder A was Volume of A=π×9×5=45πcm3\text{Volume of A} = \pi \times 9 \times 5 = 45\pi \, \text{cm}^3.
    • Therefore, the volume of Cylinder B is 8×45π=360πcm38 \times 45\pi = 360\pi \, \text{cm}^3.

    Converting to a decimal: VB360×3.1416=1130.97cm3V_B \approx 360 \times 3.1416 = 1130.97 \, \text{cm}^3

So, the correct volume of Cylinder B is approximately 1131 cm³.

Would you like any further details or have additional questions? Here are some related questions:

  1. How would the volume of Cylinder B change if the height was 15 cm instead of 10 cm?
  2. How does the concept of mathematical similarity apply to other geometric shapes, like cones or spheres?
  3. If the radius of Cylinder A was doubled, what would be the new volume of Cylinder B?
  4. What is the relationship between the surface area ratio and volume ratio in similar figures?
  5. How can you determine the surface area of Cylinder B using the similarity ratio?

Tip: When dealing with similar figures, always remember that the ratio of volumes is the cube of the ratio of corresponding linear dimensions.

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Math Problem Analysis

Mathematical Concepts

Similarity of Shapes
Volumes of Cylinders

Formulas

Volume of Cylinder: V = \pi r^2 h

Theorems

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Suitable Grade Level

Advanced High School