Math Problem Statement

f(x)f\left(x\right)=x\sqrt{x}, g(x) = x+9, functions, find a. (f∘g)(x)(f∘g)(x) and b. (g∘f)(x)(g∘f)(x) Simplify

Solution

Let's solve the given problem step by step.

Given the functions:

  • f(x)=xf(x) = \sqrt{x}
  • g(x)=x+9g(x) = x + 9

Part a: (fg)(x)(f \circ g)(x)

This represents the composition of the functions ff and gg, where ff is applied after gg. Mathematically, it can be expressed as:

(fg)(x)=f(g(x))(f \circ g)(x) = f(g(x))

Substitute g(x)=x+9g(x) = x + 9 into f(x)=xf(x) = \sqrt{x}:

(fg)(x)=f(x+9)=x+9(f \circ g)(x) = f(x + 9) = \sqrt{x + 9}

So, (fg)(x)=x+9(f \circ g)(x) = \sqrt{x + 9}.

Part b: (gf)(x)(g \circ f)(x)

This represents the composition of the functions gg and ff, where gg is applied after ff. Mathematically, it can be expressed as:

(gf)(x)=g(f(x))(g \circ f)(x) = g(f(x))

Substitute f(x)=xf(x) = \sqrt{x} into g(x)=x+9g(x) = x + 9:

(gf)(x)=g(x)=x+9(g \circ f)(x) = g(\sqrt{x}) = \sqrt{x} + 9

So, (gf)(x)=x+9(g \circ f)(x) = \sqrt{x} + 9.

Final Answers:

a. (fg)(x)=x+9(f \circ g)(x) = \sqrt{x + 9}

b. (gf)(x)=x+9(g \circ f)(x) = \sqrt{x} + 9

Would you like more details or have any questions?

Here are five related questions:

  1. What is the domain of the function f(x)=xf(x) = \sqrt{x}?
  2. How do you find the domain of a composite function like (fg)(x)(f \circ g)(x)?
  3. What happens to the range of g(x)=x+9g(x) = x + 9 when composed with f(x)=xf(x) = \sqrt{x}?
  4. How do you determine if a function is one-to-one or onto?
  5. How can you graph the functions f(x)f(x) and g(x)g(x) and their compositions?

Tip: Always verify the domain and range of the composed function to ensure it makes sense within the context of the original functions.

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Math Problem Analysis

Mathematical Concepts

Functions
Composition of Functions
Square Root Function
Linear Function

Formulas

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Theorems

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Suitable Grade Level

Grades 9-12