The sequence provided (3, 7, 11, 15, 19) is an example of an arithmetic sequence where each term increases by a common difference. In this case, the common difference is 4. To skip count by 4 starting from 3, you add 4 to each term to get the next one.

Here's the detailed process of generating the next terms:

- Start with 3.
- Add 4 to 3 to get 7.
- Add 4 to 7 to get 11.
- Add 4 to 11 to get 15.
- Add 4 to 15 to get 19.
- Add 4 to 19 to get 23.
- Add 4 to 23 to get 27.
- Add 4 to 27 to get 31.
- Add 4 to 31 to get 35.

So, the sequence continues as: 3, 7, 11, 15, 19, 23, 27, 31, 35, ...

Would you like more details or have any questions?

Here are 8 relative questions that expand on this information:

1. What is an arithmetic sequence?
2. How do you find the common difference in an arithmetic sequence?
3. Can you derive the nth term formula for an arithmetic sequence?
4. How would you identify if a sequence is arithmetic or geometric?
5. What are some real-world examples of arithmetic sequences?
6. How can you find the sum of the first n terms of an arithmetic sequence?
7. What happens if the common difference in an arithmetic sequence is negative?
8. How can you apply arithmetic sequences in solving algebraic problems?

**Tip:** Always check your common difference in an arithmetic sequence by subtracting any term from the previous one to ensure consistency.

Explore arithmetic sequences by understanding skip counting using the sequence 3, 7, 11, 15, 19. Learn the nth term formula for arithmetic sequences and how to identify and extend such sequences. Suitable for students in Grades 7-9.

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