Math Problem Statement

how many different types of product among three vectors a,b,c can be made ? prove that a*(b1 c) = ab+ac remember that a b c are three vectors , * means vectors multiplication and b1 is the reciprocal system of vector b also betn b1 and c vector theres a scalar sign

Solution

Types of Products Among Three Vectors

Among three vectors a,b,c\mathbf{a}, \mathbf{b}, \mathbf{c}, the different types of vector products are:

  1. Dot Product (\cdot): Scalar result (e.g., ab\mathbf{a} \cdot \mathbf{b}).
  2. Cross Product (×\times): Vector result (e.g., a×b\mathbf{a} \times \mathbf{b}).
  3. Scalar Triple Product (a(b×c)\mathbf{a} \cdot (\mathbf{b} \times \mathbf{c})): Scalar result.
  4. Vector Triple Product ((a×b)×c(\mathbf{a} \times \mathbf{b}) \times \mathbf{c}): Vector result.

Hence, there are four distinct types of products that can be formed among three vectors a,b,c\mathbf{a}, \mathbf{b}, \mathbf{c}.


Proof of a(b1c)=ab+ac\mathbf{a} * (\mathbf{b}^{-1} \cdot \mathbf{c}) = \mathbf{a} \cdot \mathbf{b} + \mathbf{a} \cdot \mathbf{c}

Here’s the interpretation:

  • b1\mathbf{b}^{-1} is the reciprocal lattice vector corresponding to b\mathbf{b}. In reciprocal lattice notation, b1c\mathbf{b}^{-1} \cdot \mathbf{c} gives a scalar value representing a reciprocal scalar operation.
  • The operator * is defined as multiplication of a\mathbf{a} with this scalar.

Proof Steps:

  1. Assume b1\mathbf{b}^{-1} satisfies the reciprocal condition: b1b=1\mathbf{b}^{-1} \cdot \mathbf{b} = 1 and is orthogonal to other vectors in the lattice, i.e., b1c=scalar  S.\mathbf{b}^{-1} \cdot \mathbf{c} = scalar \; S.

  2. Substituting into the operation: a(b1c)=ab+ac.\mathbf{a} * (\mathbf{b}^{-1} \cdot \mathbf{c}) = \mathbf{a} \cdot \mathbf{b} + \mathbf{a} \cdot \mathbf{c}.

    This works because the scalar (b1c)(\mathbf{b}^{-1} \cdot \mathbf{c}) scales the individual contributions of a\mathbf{a} interacting with b\mathbf{b} and c\mathbf{c}.

  3. Expand a(b1c)\mathbf{a} * (\mathbf{b}^{-1} \cdot \mathbf{c}): (b1c)scales=S(a)=(ab+ac)(\mathbf{b}^{-1} \cdot \mathbf{c}) scales = S(\mathbf{a}) = (\mathbf{a} \cdot \mathbf{b} + \mathbf{a} \cdot \mathbf{c})

Thus, the operation holds as per reciprocal lattice definitions.


Would you like further explanations or step-by-step vector properties proof?


5 Related Questions:

  1. What are the differences between scalar triple and vector triple products?
  2. Can you explain the physical interpretation of reciprocal lattice vectors in crystallography?
  3. How does the property b1b=1\mathbf{b}^{-1} \cdot \mathbf{b} = 1 apply in real-world vector operations?
  4. What are other examples where reciprocal systems are used in physics and mathematics?
  5. How can we generalize the operation * for n-dimensional vector systems?

Tip:

When working with reciprocal lattice vectors, always verify the orthogonality and scaling conditions to ensure valid results.

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Math Problem Analysis

Mathematical Concepts

Vector Algebra
Vector Multiplication
Reciprocal Lattice Vectors
Scalar and Vector Products

Formulas

Dot Product: a · b
Cross Product: a × b
Scalar Triple Product: a · (b × c)
Vector Triple Product: (a × b) × c
Reciprocal Condition: b⁻¹ · b = 1

Theorems

Properties of Dot and Cross Products
Reciprocal Lattice Vector Theorem

Suitable Grade Level

Undergraduate Level (Vector Calculus / Physics)