Math Problem Statement

tan θ = 4/3 ; 180° < θ < 270°

Solution

We are given that tanθ=43\tan \theta = \frac{4}{3} and that 180<θ<270180^\circ < \theta < 270^\circ. This range corresponds to the third quadrant, where both sine and cosine are negative, and tangent is positive.

Step-by-Step Solution:

  1. Identify the Reference Triangle:

    • The tangent of an angle in a right triangle is given by tanθ=oppositeadjacent\tan \theta = \frac{\text{opposite}}{\text{adjacent}}. Here, the opposite side is 4, and the adjacent side is 3. Since θ\theta is in the third quadrant, both the opposite and adjacent sides will have negative values: 4-4 and 3-3.
  2. Calculate the Hypotenuse: Use the Pythagorean theorem: r=(4)2+(3)2=16+9=25=5r = \sqrt{(-4)^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5

  3. **Determine sinθ\sin \theta and \

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Right Triangles
Quadrants

Formulas

tan θ = opposite / adjacent
Pythagorean theorem: r = √(opposite² + adjacent²)
sin θ = opposite / hypotenuse
cos θ = adjacent / hypotenuse

Theorems

Pythagorean theorem
Trigonometric function properties in quadrants

Suitable Grade Level

Grades 10-12