You have provided an expression that looks like it involves trigonometric terms. Here's the correct interpretation of the expression:

\[
s = \frac{4}{3\pi} \sin(3t) + \frac{4}{5\pi} \cos(5t)
\]

### Explanation:
- \( \frac{4}{3\pi} \sin(3t) \) is the first term, involving a sine function with amplitude \( \frac{4}{3\pi} \) and frequency 3.
- \( \frac{4}{5\pi} \cos(5t) \) is the second term, involving a cosine function with amplitude \( \frac{4}{5\pi} \) and frequency 5.

Let me know if you'd like me to go into further details, or have questions! 

Here are some related questions:
1. How do we find the amplitude of the function \( s \)?
2. How can we express this function in terms of a single trigonometric function?
3. What is the period of this function?
4. How do we calculate the phase shift of a trigonometric function?
5. What is the effect of adding these two functions together?

**Tip:** When dealing with trigonometric functions, keep in mind the difference between amplitude, frequency, and phase shift for deeper understanding.

Explore the trigonometric expression s = 4/3π sin(3t) + 4/5π cos(5t), including the calculation of amplitude, period, and frequency. Suitable for students in Grades 10-12, this page offers a detailed explanation of the properties of sine and cosine functions.

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