Math Problem Statement

Find the value of x^0 in each of the following triangles (provided in the image).

Solution

Let's analyze the three triangles to find the value of xx^\circ for each.

a) Triangle a:

  • This is a standard triangle with all three angles labeled. The known angles are 4242^\circ and 7272^\circ.
  • Since the sum of the angles in a triangle is always 180180^\circ, we can find xx^\circ by: x=180(42+72)=180114=66x^\circ = 180^\circ - (42^\circ + 72^\circ) = 180^\circ - 114^\circ = 66^\circ Therefore, x=66x^\circ = 66^\circ.

b) Triangle b:

  • This triangle has an external angle labeled as 150150^\circ.
  • The external angle of a triangle is equal to the sum of the two opposite interior angles. In this case, xx^\circ is one of those opposite angles. Let yy^\circ be the other interior angle.
  • The equation for the external angle is: 150=x+y150^\circ = x^\circ + y^\circ
    • There is a 3030^\circ angle inside the triangle. Since the sum of angles in a triangle is 180180^\circ, the third angle yy^\circ can be calculated: y=180(150+30)=180180=0y^\circ = 180^\circ - (150^\circ + 30^\circ) = 180^\circ - 180^\circ = 0^\circ

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Triangle Angles
External Angles

Formulas

Sum of angles in a triangle = 180°
External angle of a triangle = sum of two opposite interior angles

Theorems

Angle Sum Theorem
Exterior Angle Theorem

Suitable Grade Level

Grades 7-9