Math Problem Statement

Let T = (V, E) be a tree, and let u, v € V be any two nodes. Prove that the height of the rooted tree (T, u) is at most twice the height of the rooted tree (T, v).

Solution

To prove that the height of the rooted tree (T,u)(T, u) is at most twice the height of the rooted tree (T,v)(T, v), we proceed as follows:

Definitions and Key Facts

  1. Tree Definition: A tree is an acyclic connected graph.
  2. Height of a Rooted Tree: The height of a rooted tree (T,r)(T, r) is the maximum distance from the root rr to any other node in the tree.
  3. Distances in a Tree: In a tree, the distance between any two nodes xx and yy, denoted d(x,y)d(x, y), is the length of the unique path between them.

Let the height of (T,u)(T, u) be huh_u and the height of (T,v)(T, v) be hvh_v.

Argument

  1. Re-rooting the Tree: When a tree is rooted at a node uu, the height is determined by the maximum distance from uu to any other node wVw \in V, i.e., hu=maxwVd(u,w)h_u = \max_{w \in V} d(u, w). Similarly, hv=maxwVd(v,w)h_v = \max_{w \in V} d(v, w).

  2. Key Idea: The distances in a tree satisfy the triangle inequality: d(u,w)d(u,v)+d(v,w).d(u, w) \leq d(u, v) + d(v, w). Similarly, reversing the roles of uu and vv: d(v,w)d(v,u)+d(u,w).d(v, w) \leq d(v, u) + d(u, w).

  3. Bounding huh_u:

    • For any wVw \in V, the distance from uu to ww satisfies: d(u,w)d(u,v)+d(v,w).d(u, w) \leq d(u, v) + d(v, w).
    • Taking the maximum over all wVw \in V to compute the height huh_u: hu=maxwVd(u,w)d(u,v)+maxwVd(v,w).h_u = \max_{w \in V} d(u, w) \leq d(u, v) + \max_{w \in V} d(v, w).
    • Hence: hud(u,v)+hv.h_u \leq d(u, v) + h_v.
  4. Bounding hvh_v:

    • Similarly, for any wVw \in V, the distance from vv to ww satisfies: d(v,w)d(v,u)+d(u,w).d(v, w) \leq d(v, u) + d(u, w).
    • Taking the maximum over all wVw \in V to compute the height hvh_v: hv=maxwVd(v,w)d(v,u)+maxwVd(u,w).h_v = \max_{w \in V} d(v, w) \leq d(v, u) + \max_{w \in V} d(u, w).
    • Hence: hvd(v,u)+hu.h_v \leq d(v, u) + h_u.
  5. Relating the Heights:

    • From the bounds above: hud(u,v)+hvandhvd(v,u)+hu.h_u \leq d(u, v) + h_v \quad \text{and} \quad h_v \leq d(v, u) + h_u.
    • Since d(u,v)=d(v,u)d(u, v) = d(v, u), combining these inequalities: huhv+d(u,v)andhvhu+d(u,v).h_u \leq h_v + d(u, v) \quad \text{and} \quad h_v \leq h_u + d(u, v).
    • Adding these two inequalities: hu+hv2hv+2d(u,v).h_u + h_v \leq 2h_v + 2d(u, v).
    • Simplify to find: hu2hv.h_u \leq 2h_v.

Conclusion

The height of the rooted tree (T,u)(T, u) is at most twice the height of the rooted tree (T,v)(T, v): hu2hv.h_u \leq 2h_v.

This completes the proof.


Do you want additional details or have any questions about this proof? Here are some related questions to explore:

  1. What are some examples of trees where the height inequality is tight (i.e., hu=2hvh_u = 2h_v)?
  2. How does re-rooting affect the diameter of a tree?
  3. Can we generalize this result to graphs that are not trees?
  4. What is the significance of the triangle inequality in proving properties of trees?
  5. How does this result relate to the concept of eccentricity in graph theory?

Tip: When proving inequalities in graph theory, carefully use properties like the triangle inequality and uniqueness of paths in trees

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Math Problem Analysis

Mathematical Concepts

Graph Theory
Trees
Height of a Tree
Triangle Inequality

Formulas

Height of a tree rooted at u: h_u = max_{w in V} d(u, w)
Triangle inequality: d(u, w) <= d(u, v) + d(v, w)

Theorems

Properties of Tree Heights
Triangle Inequality in Graphs

Suitable Grade Level

Undergraduate Level