Math Problem Statement

Luas

Luas

Solution

To calculate the area (or "luas") of the given shape, we need to break it down into simpler components. The shape appears to be a trapezoid with some additional triangular portions on the sides.

Breakdown:

  • Main rectangle: Dimensions are 20 cm by 5 cm.
  • Two triangles on the left and right sides:
    • Left triangle: Has a base of 11 cm and height of 5 cm.
    • Right triangle: Has a base of 13 cm and height of 5 cm.

Area of the main rectangle:

Area of rectangle=Length×Width=20cm×5cm=100cm2\text{Area of rectangle} = \text{Length} \times \text{Width} = 20 \, \text{cm} \times 5 \, \text{cm} = 100 \, \text{cm}^2

Area of the two triangles:

  • Left triangle (base = 11 cm, height = 5 cm): Area of left triangle=12×base×height=12×11cm×5cm=27.5cm2\text{Area of left triangle} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 11 \, \text{cm} \times 5 \, \text{cm} = 27.5 \, \text{cm}^2

  • Right triangle (base = 13 cm, height = 5 cm): Area of right triangle=12×base×height=12×13cm×5cm=32.5cm2\text{Area of right triangle} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 13 \, \text{cm} \times 5 \, \text{cm} = 32.5 \, \text{cm}^2

Total Area:

Total Area=100cm2+27.5cm2+32.5cm2=160cm2\text{Total Area} = 100 \, \text{cm}^2 + 27.5 \, \text{cm}^2 + 32.5 \, \text{cm}^2 = 160 \, \text{cm}^2

The total area of the shape is 160 cm².

Would you like further details or have any questions?

Here are 5 related questions to think about:

  1. How would the area change if the height of the triangles increased?
  2. How do we find the perimeter of this shape?
  3. Can this shape be divided into any other combinations of geometric figures?
  4. What is the importance of correctly identifying the dimensions of a shape in real-world applications?
  5. How would the calculation change if this were a 3D shape, such as a prism?

Tip: When breaking down complex shapes into simpler components, always look for standard geometric figures like triangles, rectangles, or trapezoids to simplify area calculations.

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Math Problem Analysis

Mathematical Concepts

Geometry
Area Calculation

Formulas

Area of rectangle = Length × Width
Area of triangle = 1/2 × base × height

Theorems

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Suitable Grade Level

Grades 5-7