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The problem states:

"A square painting of side length 30 cm is to be framed with timber of width 5 cm. Find the total length of timber required for the job."

### Solution:

1. The side length of the square painting is 30 cm.
2. The timber adds a width of 5 cm on each side, so the total side length of the square including the frame is:
   \[
   30 \, \text{cm} + 2 \times 5 \, \text{cm} = 40 \, \text{cm}
   \]
3. The total length of timber required is the perimeter of the outer square (including the frame).

The formula for the perimeter of a square is:
\[
\text{Perimeter} = 4 \times \text{side length}
\]
Substituting the side length of 40 cm:
\[
\text{Perimeter} = 4 \times 40 \, \text{cm} = 160 \, \text{cm}
\]

Thus, the total length of timber required is **160 cm**.

Would you like more details or have any questions?

### Related Questions:
1. What would the total length of timber be if the painting had a rectangular shape?
2. How would the calculation change if the frame was not of uniform width on all sides?
3. If the timber costs $2 per meter, what would be the total cost for the required timber?
4. What is the area of the painting before and after framing?
5. How would the perimeter change if the timber width was increased to 10 cm?

### Tip:
Always double-check dimensions and ensure you account for both the painting and the frame when calculating perimeter or area for framed objects.

A square painting of side length 30 cm is to be framed with timber of width 5 cm. Find the total length of timber required for the job.

Calculate the total length of timber needed to frame a square painting with a side length of 30 cm and a 5 cm wide timber frame. This geometry problem involves calculating the perimeter of a square after including the frame width. Suitable for middle school students in Grades 6-8.

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