Math Problem Statement

Annabelle invested $27,000 in an account paying an interest rate of 4 1/4% compounded monthly. Avery invested $27,000 in an account paying an interest rate of 3 7/8% compounded daily. To the nearest hundredth of a year, how much longer would it take for Avery's money to triple than for Annabelle's money to triple?

Solution

The problem asks us to compare the time it takes for two different investments to triple in value, one for Annabelle and one for Avery. Here's how we can break it down:

Information:

  • Annabelle's account:
    • Initial investment: $27,000
    • Interest rate: 414%=4.25%4 \frac{1}{4} \% = 4.25\% compounded monthly
  • Avery's account:
    • Initial investment: $27,000
    • Interest rate: 378%=3.875%3 \frac{7}{8} \% = 3.875\% compounded daily

We are asked to find how much longer it will take for Avery's investment to triple compared to Annabelle's, to the nearest hundredth of a year.

Formula for Compound Interest:

The formula for compound interest is:

A=P(1+rn)ntA = P \left(1 + \frac{r}{n}\right)^{nt}

Where:

  • AA is the final amount.
  • PP is the principal (initial amount).
  • rr is the annual interest rate in decimal form.
  • nn is the number of times interest is compounded per year.
  • tt is the time in years.

We need to solve for tt, the time it takes for the money to triple. This means we need to set A=3PA = 3P, so:

3P=P(1+rn)nt3P = P \left(1 + \frac{r}{n}\right)^{nt}

Canceling out PP from both sides:

3=(1+rn)nt3 = \left(1 + \frac{r}{n}\right)^{nt}

Now, solve for tt by taking the natural logarithm on both sides:

ln(3)=ntln(1+rn)\ln(3) = nt \cdot \ln\left(1 + \frac{r}{n}\right)

t=ln(3)nln(1+rn)t = \frac{\ln(3)}{n \cdot \ln\left(1 + \frac{r}{n}\right)}

For Annabelle:

  • r=0.0425r = 0.0425
  • n=12n = 12 (since it's compounded monthly)

tAnnabelle=ln(3)12ln(1+0.042512)t_{Annabelle} = \frac{\ln(3)}{12 \cdot \ln\left(1 + \frac{0.0425}{12}\right)}

For Avery:

  • r=0.03875r = 0.03875
  • n=365n = 365 (since it's compounded daily)

tAvery=ln(3)365ln(1+0.03875365)t_{Avery} = \frac{\ln(3)}{365 \cdot \ln\left(1 + \frac{0.03875}{365}\right)}

Finally, to answer the question, we need to find the difference in time:

Δt=tAverytAnnabelle\Delta t = t_{Avery} - t_{Annabelle}

Let me compute the values.- Annabelle's money will triple in approximately 25.90 years.

  • Avery's money will triple in approximately 28.35 years.
  • The difference is about 2.46 years.

Thus, it will take Avery about 2.46 years longer than Annabelle for their investments to triple.

Would you like further details or have any questions? Here are 5 related questions to explore further:

  1. How would the time change if the interest rate for Avery increased to 4%?
  2. What happens if both accounts are compounded annually instead of monthly or daily?
  3. How much time would it take for the investments to quadruple instead of triple?
  4. Can you explain the effect of compounding frequency on the time to triple for both accounts?
  5. How would different principal amounts affect the results?

Tip: Compounding frequency can have a significant effect on the growth of an investment, especially over long periods. Always consider whether interest is compounded annually, monthly, or daily.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Compound Interest
Exponential Growth
Logarithms

Formulas

A = P(1 + r/n)^(nt)
t = ln(A/P) / [n * ln(1 + r/n)]

Theorems

Compound Interest Growth Model

Suitable Grade Level

Grades 10-12