Math Problem Statement

The data table contains waiting times of customers at a​ bank, where customers enter a single waiting line that feeds three teller windows. Test the claim that the standard deviation of waiting times is less than 2.22.2 ​minutes, which is the standard deviation of waiting times at the same bank when separate waiting lines are used at each teller window. Use a significance level of 0.050.05. Assume that the sample is a simple random sample selected from a normally distributed population. Complete parts​ (a) through​ (d) below.

Solution

To test whether the standard deviation of waiting times in the single waiting line setup is less than 2.2 minutes, we will perform a hypothesis test for a population standard deviation using a chi-square distribution. The steps are outlined as follows:

(a) State the Hypotheses:

  1. Null Hypothesis (H₀): The standard deviation of waiting times, σ\sigma, is equal to or greater than 2.2 minutes. H0:σ2.2H₀: \sigma \geq 2.2

  2. Alternative Hypothesis (H₁): The standard deviation of waiting times, σ\sigma, is less than 2.2 minutes. H1:σ<2.2H₁: \sigma < 2.2

(b) Determine the Significance Level and Identify the Critical Value:

  • Given the significance level, α=0.05\alpha = 0.05.
  • We will use a chi-square distribution for this test since it is based on the sample variance.

Let:

  • nn = sample size (number of customers in the data table).
  • ss = sample standard deviation of waiting times (calculated from the data).

The test statistic for testing the population variance σ2\sigma^2 is: χ2=(n1)s2σ2\chi^2 = \frac{(n - 1)s^2}{\sigma^2} where σ2=2.22=4.84\sigma^2 = 2.2^2 = 4.84.

To find the critical value, we use the chi-square distribution table for n1n - 1 degrees of freedom at the 0.05 significance level for a left-tailed test.

(c) Calculate the Test Statistic:

Using the sample data provided, calculate the sample standard deviation ss and then apply it in the formula for the test statistic χ2\chi^2.

(d) Make a Decision:

  1. If the calculated χ2\chi^2 is less than the critical value from the chi-square table, we reject the null hypothesis.
  2. Otherwise, we fail to reject the null hypothesis.

If you can provide the data in the table or the sample size and standard deviation calculated from it, I can assist with the actual computations.

Would you like details on calculating the sample standard deviation or interpreting chi-square critical values?

Follow-Up Questions:

  1. What is the procedure to calculate the sample standard deviation from raw data?
  2. How does the chi-square distribution differ for left-tailed and right-tailed tests?
  3. Why do we use the chi-square test for population variance instead of other tests?
  4. How is the decision affected if we change the significance level to a higher or lower value?
  5. How does the interpretation change if the sample is not normally distributed?

Tip: When using the chi-square test, always check if the sample data meets the normality assumption, as this affects test validity.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Standard Deviation
Chi-Square Distribution

Formulas

Chi-square test statistic: χ² = ((n - 1) * s²) / σ²
Standard deviation of the alternative scenario: σ = 2.2

Theorems

Chi-Square Test for Population Standard Deviation

Suitable Grade Level

College-level Statistics