Math Problem Statement

solve

Solution

Let's work through the problem step by step.

Given:

f(x)=x2x2+3f(x) = \frac{x^2}{x^2 + 3}

(a) Find the first Taylor polynomial T1(x)T_1(x) at x=0x = 0 for f(x)f(x).

To find the first Taylor polynomial T1(x)T_1(x), we need to find the value of f(0)f(0) and the first derivative f(0)f'(0).

  1. Compute f(0)f(0):

    f(0)=0202+3=0f(0) = \frac{0^2}{0^2 + 3} = 0

  2. Compute f(x)f'(x):

    We use the quotient rule to differentiate f(x)f(x).

    If f(x)=g(x)h(x)f(x) = \frac{g(x)}{h(x)}, then f(x)=g(x)h(x)g(x)h(x)(h(x))2f'(x) = \frac{g'(x)h(x) - g(x)h'(x)}{(h(x))^2}

    Here, g(x)=x2g(x) = x^2 and h(x)=x2+3h(x) = x^2 + 3.

    • g(x)=2xg'(x) = 2x
    • h(x)=2xh'(x) = 2x

    Then: f(x)=(2x)(x2+3)(x2)(2x)(x2+3)2f'(x) = \frac{(2x)(x^2 + 3) - (x^2)(2x)}{(x^2 + 3)^2} Simplifying this: f(x)=2x(x2+3x2)(x2+3)2=6x(x2+3)2f'(x) = \frac{2x(x^2 + 3 - x^2)}{(x^2 + 3)^2} = \frac{6x}{(x^2 + 3)^2}

  3. Evaluate f(0)f'(0):

    f(0)=6×0(02+3)2=0f'(0) = \frac{6 \times 0}{(0^2 + 3)^2} = 0

The first Taylor polynomial T1(x)T_1(x) at x=0x = 0 is: T1(x)=f(0)+f(0)x=0+0x=0T_1(x) = f(0) + f'(0)x = 0 + 0 \cdot x = 0

(b) Use the Taylor polynomial to approximate f(1.05)f(1.05).

Since the first Taylor polynomial T1(x)=0T_1(x) = 0, the approximation is: f(1.05)T1(1.05)=0f(1.05) \approx T_1(1.05) = 0

(c) Calculate the error in the Taylor Series approximation f(1.05)T1(1.05)|f(1.05) - T_1(1.05)|.

To find the error, we calculate the exact value of f(1.05)f(1.05): f(1.05)=(1.05)2(1.05)2+3f(1.05) = \frac{(1.05)^2}{(1.05)^2 + 3} I'll compute this numerically.

Let's calculate that value.The exact value of f(1.05)f(1.05) is approximately 0.26870.2687.

Error Calculation

Since the Taylor polynomial approximation T1(1.05)=0T_1(1.05) = 0, the error is: Error=f(1.05)T1(1.05)=0.26870=0.2687\text{Error} = |f(1.05) - T_1(1.05)| = |0.2687 - 0| = 0.2687

Summary:

  1. The first Taylor polynomial T1(x)T_1(x) at x=0x = 0 is 00.
  2. The approximation of f(1.05)f(1.05) using T1(x)T_1(x) is 00.
  3. The error in the Taylor Series approximation is approximately 0.26870.2687.

Would you like more details or have any other questions?

Here are 5 related questions to explore:

  1. How would the Taylor polynomial change if we considered more terms in the expansion?
  2. What is the second derivative f(x)f''(x) at x=0x = 0?
  3. How does the error change if you use the second Taylor polynomial instead of the first?
  4. What is the interval of convergence for the Taylor series of f(x)f(x)?
  5. How can we use Taylor series to approximate functions near points other than x=0x = 0?

Tip: When working with Taylor series, increasing the number of terms generally improves the accuracy of approximations.

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Math Problem Analysis

Mathematical Concepts

Taylor series
First derivative
Error estimation

Formulas

Taylor polynomial
Quotient rule

Theorems

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Suitable Grade Level

Advanced undergraduate level