Math Problem Statement
write the eq of a line tangent to y=tan(2x) at x=pi/12
Solution
To find the equation of the line tangent to the function at , follow these steps:
1. Find the derivative of
The derivative of gives the slope of the tangent line. Using the chain rule, we differentiate :
2. Evaluate the slope at
Substitute into the derivative to find the slope of the tangent line at this point:
We know , so:
The slope of the tangent line is 8.
3. Find the y-coordinate at
Substitute into the original function :
We know , so the y-coordinate at is .
4. Use the point-slope form to write the equation of the tangent line
The point-slope form of a line is:
where is the slope and is the point on the curve. We have , , and . Substituting these values:
This is the equation of the tangent line.
Would you like more details or have any questions?
Here are some related questions you might want to explore:
- How do you find the normal line to a curve?
- What happens to the tangent line as the slope changes rapidly, like near asymptotes?
- Can we extend this method to find tangent lines for other trigonometric functions?
- How does the chain rule apply to differentiating composite functions in other contexts?
- How does the derivative of a trigonometric function change with different amplitudes and frequencies?
Tip: When dealing with trigonometric functions, it's often helpful to review the values of sine, cosine, and tangent at key angles, such as and .
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Calculus
Derivatives
Tangent Line
Formulas
Derivative of y = tan(2x): dy/dx = 2 sec^2(2x)
Point-slope form: y - y1 = m(x - x1)
Theorems
Chain Rule
Suitable Grade Level
Grades 11-12