Math Problem Statement

7. A cone and a cylinder have the same height h and are equivalent in volume. Let r represent the radius of the cylinder. What is the radius of the cone? 8. The rectangular prism and the cube on the right are equivalent in volume. By how much does the total area of the prism surpass the total area of the cube? 9. A prism, a cylinder and a cone are equivalent. If the bases of the prism, the cylinder and the cone are equivalent, compare a) the heights of the prism and the cylinder; b) the heights of the prism and the cone. 10. A sculpture is formed by a pyramid mounted on top of a cube. The cube and the pyramid are equivalent. Determine the total height of the sculpture if its volume is equal to 432 cm³.

Solution

Let's break down the problems one by one:

Question 7:

A cone and a cylinder have the same height hh and are equivalent in volume. Let rr represent the radius of the cylinder. We are to determine the radius of the cone.

Key points:

  • Volume of a cylinder: Vcylinder=πr2hV_{\text{cylinder}} = \pi r^2 h
  • Volume of a cone: Vcone=13πrcone2hV_{\text{cone}} = \frac{1}{3} \pi r_{\text{cone}}^2 h

Since their volumes are equal: πr2h=13πrcone2h\pi r^2 h = \frac{1}{3} \pi r_{\text{cone}}^2 h

From this, we can solve for the radius rconer_{\text{cone}} of the cone.

Question 8:

The rectangular prism and cube on the right are equivalent in volume. By how much does the total area of the prism surpass the total area of the cube?

Key points:

  • Cube side length is xx, so the surface area of the cube is 6x26x^2.
  • Rectangular prism dimensions are (x2)(x-2), x+4x+4, and xx, so its surface area is calculated as: Area of prism=2[(x2)(x+4)+(x2)x+(x+4)x]\text{Area of prism} = 2[(x-2)(x+4) + (x-2)x + (x+4)x] Now, subtract the cube's surface area from the prism's surface area to find the difference.

Question 9:

A prism, cylinder, and cone are equivalent in volume. If the bases are equivalent:

  1. Compare the heights of the prism and the cylinder.
  2. Compare the heights of the prism and the cone.

Question 10:

A sculpture is formed by a pyramid mounted on top of a cube, with the volumes of the cube and pyramid equivalent. The total volume of the sculpture is 432 cm³. We are to find the total height of the sculpture.

Key points:

  • Volume of cube: Vcube=s3V_{\text{cube}} = s^3
  • Volume of pyramid: Vpyramid=13s2hpyramidV_{\text{pyramid}} = \frac{1}{3} s^2 h_{\text{pyramid}}

Since the total volume of the sculpture is known, we can express the total volume as the sum of the cube and pyramid volumes: Vcube+Vpyramid=432 cm3V_{\text{cube}} + V_{\text{pyramid}} = 432 \text{ cm}^3

Now solve for the side length ss and total height htotalh_{\text{total}}.


Let me know which part you'd like to focus on first or if you'd like further clarification! Here's how you can expand your understanding:

  1. How are the volumes of cylinders and cones calculated in other scenarios?
  2. How does the surface area change for various 3D shapes?
  3. How are the relationships between height and volume compared for different shapes?
  4. How does symmetry play a role in shape comparison problems?
  5. What other examples can you think of where two shapes have equivalent volumes?

Tip: Always check if units are consistent when calculating areas and volumes to avoid mistakes.

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Math Problem Analysis

Mathematical Concepts

Geometry
Volume
Surface Area
Equivalency of Solids
Algebraic Expressions

Formulas

Volume of cylinder: V_cylinder = πr²h
Volume of cone: V_cone = (1/3)πr²h
Surface area of cube: 6x²
Surface area of rectangular prism: 2[(x-2)(x+4) + (x-2)x + (x+4)x]
Volume of cube: V_cube = s³
Volume of pyramid: V_pyramid = (1/3)s²h

Theorems

Volume equivalency
Surface area comparison
Symmetry in geometric shapes

Suitable Grade Level

Grades 8-10