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To find the surface area of a cuboid, we use the formula:

\[
\text{Surface Area} = 2(lw + lh + wh)
\]

Where:
- \( l = 9 \, \text{cm} \) (length),
- \( w = 20 \, \text{cm} \) (width),
- \( h = 16 \, \text{cm} \) (height).

Now, let's calculate:

1. \( lw = 9 \times 20 = 180 \, \text{cm}^2 \)
2. \( lh = 9 \times 16 = 144 \, \text{cm}^2 \)
3. \( wh = 20 \times 16 = 320 \, \text{cm}^2 \)

Adding these up:
\[
lw + lh + wh = 180 + 144 + 320 = 644 \, \text{cm}^2
\]

Finally, multiplying by 2:
\[
\text{Surface Area} = 2 \times 644 = 1288 \, \text{cm}^2
\]

So, the surface area of the cuboid is **1288 cm²**.

Would you like more details on the process or have any questions?

Here are five follow-up questions for further practice:
1. What would the surface area be if the length was increased to 12 cm?
2. How does the surface area change if the height is halved?
3. What is the volume of the cuboid with the given dimensions?
4. If the width were doubled, how would that affect the surface area?
5. How do you calculate the lateral surface area of a cuboid?

**Tip:** The surface area of a cuboid involves adding the areas of all six faces—be sure to account for all dimensions twice when calculating!

A cuboid has a length of 9 cm, a width of 20 cm, and a height of 16 cm. What is the surface area of the cuboid? Give your answer in cm².

Learn how to calculate the surface area of a cuboid with a length of 9 cm, width of 20 cm, and height of 16 cm. This problem includes key geometric concepts and the surface area formula for cuboids. Suitable for students in Grades 6-8.

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