Math Problem Statement

how they have written the series?

How they have written the series?

Solution

The image shows a series representation which involves a summation and logarithmic terms. Here's a breakdown of the mathematical expression they've written:

The series is written as:

n=1xnn+k=1xk(x+x22++xkk+log(1x))\sum_{n=1}^{\infty} \frac{x^n}{n+k} = -\frac{1}{x^k} \left( x + \frac{x^2}{2} + \dots + \frac{x^k}{k} + \log(1-x) \right)

Where:

  • The summation starts from n=1n = 1 and goes to infinity, involving terms of the form xnn+k\frac{x^n}{n+k}.
  • The right-hand side is a closed form that involves several components:
    • 1xk-\frac{1}{x^k} is a multiplying factor.
    • Inside the parentheses, we have a series that involves the powers of xx up to xkk\frac{x^k}{k}, followed by the logarithmic term log(1x)\log(1-x).

The expression applies when:

  • kk is a positive integer.
  • x<1|x| < 1.

Would you like more details about how this series is derived, or do you have specific questions?

Here are 5 related questions you might consider:

  1. What is the logarithmic series, and how is it related to the sum?
  2. How does the convergence of the series depend on x<1|x| < 1?
  3. How is this series used in approximations for small values of xx?
  4. Can you derive the log(1x)\log(1-x) term from the series expansion?
  5. What happens when k=1k = 1 or other specific values of kk?

Tip: Series expansions like this are helpful when approximating functions for small values of variables, especially when x<1|x| < 1.

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Math Problem Analysis

Mathematical Concepts

Series Expansion
Logarithmic Series
Summation

Formulas

\sum_{n=1}^{\infty} \frac{x^n}{n+k} = -\frac{1}{x^k} \left( x + \frac{x^2}{2} + \dots + \frac{x^k}{k} + \log(1-x) \right)

Theorems

Logarithmic Series Expansion

Suitable Grade Level

University Level (Advanced Calculus)