Math Problem Statement

Solve the summation series problems: 1. 1·2 + 2·3 + 3·4 + ... + n·(n+1) and 2. 1·4 + 2·7 + 3·10 + ... + n·(3n+1)

Solution

The image you uploaded contains two summation series problems, labeled as parts (a) and (c). Here’s a breakdown of what I can interpret from it:

Problem (a):

The series looks like:

12+23+34++n(n+1)1 \cdot 2 + 2 \cdot 3 + 3 \cdot 4 + \dots + n \cdot (n + 1)

The formula provided is:

n(n+1)(n+2)3\frac{n(n+1)(n+2)}{3}

This seems to be the closed form for the sum of the series. It simplifies the summation of the products of consecutive integers.

Problem (c):

This series appears as:

14+27+310++n(3n+1)1 \cdot 4 + 2 \cdot 7 + 3 \cdot 10 + \dots + n \cdot (3n + 1)

And the closed form given is:

n(n+1)2n(n + 1)^2

This is the compact form for the sum of the given series, which involves terms increasing with a factor of 3.

Would you like a detailed explanation for either of these problems? Let me know if you have any questions!

Here are five related questions:

  1. How would you derive the closed form for problem (a) step by step?
  2. Can you find a pattern for a similar series, such as 13+25+37+1 \cdot 3 + 2 \cdot 5 + 3 \cdot 7 + \dots?
  3. How can you generalize the sum of a series involving products of two terms?
  4. What is the meaning of the factor 13\frac{1}{3} in problem (a)'s closed form?
  5. Can you apply similar techniques to solve summations involving higher powers?

Tip: Always check for patterns in summation series by expressing a few terms and seeing if you can detect a recurrence relation or factor commonality!

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Math Problem Analysis

Mathematical Concepts

Summation series
Arithmetic progressions
Closed form

Formulas

1·2 + 2·3 + ... + n·(n+1) = n(n+1)(n+2)/3
1·4 + 2·7 + ... + n·(3n+1) = n(n+1)^2

Theorems

Summation formulas for series involving consecutive integers

Suitable Grade Level

High School (Grades 10-12)