Math Problem Statement
The series
∑n=1∞( arctan(n+2)− arctan(n))
is a telescopic series. Calculate its sum. Give the exact value.
Solution
We are given the following telescopic series:
Step 1: Express the series terms
This is a telescoping series, where consecutive terms cancel each other. To understand this cancellation better, let’s expand the first few terms:
- The first term is:
- The second term is:
- The third term is:
- The fourth term is:
- And so on...
Step 2: Observe the cancellation pattern
You can see that most terms cancel out. Specifically, for every term , the from one term cancels with the from the next term.
Thus, after the cancellation, only the first few and last terms remain:
Step 3: Take the limit
As approaches infinity, approaches because approaches as .
Thus, the sum of the series is:
Step 4: Calculate
We know that , since the tangent of is 1.
Step 5: Final sum
Now, substitute this value into the expression:
Thus, the sum of the series is:
Would you like to explore the telescoping property in more detail or ask any questions about the calculation? Here are some related questions to consider:
- What is the general form of a telescoping series?
- How does the cancellation process work in telescoping series?
- How can we apply telescoping series to other types of trigonometric functions?
- How does the concept of limits help in evaluating infinite series like this?
- Can you find a telescoping series involving other inverse trigonometric functions?
Tip: When dealing with telescoping series, it helps to write out the first few terms explicitly to understand the cancellation pattern better.
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Math Problem Analysis
Mathematical Concepts
Telescoping Series
Arctangent Function
Limits
Formulas
Sum of telescoping series
Arctan(x) formula
Limit of arctan(x) as x approaches infinity
Theorems
Telescoping series cancellation
Limit of inverse trigonometric functions
Suitable Grade Level
Grades 11-12
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