What is the sum of all natural numbers from 1 to 40

The sum of all natural numbers from 1 to 40 can be found using the formula for the sum of an arithmetic series:

\[
S_n = \frac{n}{2} \times (a + l)
\]

Where:
- \(n\) is the number of terms (in this case, 40),
- \(a\) is the first term (which is 1),
- \(l\) is the last term (which is 40).

Substitute the values:

\[
S_{40} = \frac{40}{2} \times (1 + 40) = 20 \times 41 = 820
\]

So, the sum of all natural numbers from 1 to 40 is **820**.

Would you like more details or have any questions?

Here are 5 related questions:
1. What is the sum of all natural numbers from 1 to 100?
2. How do you calculate the sum of even numbers from 1 to 40?
3. What is the sum of odd numbers from 1 to 40?
4. How can you derive the formula for the sum of an arithmetic series?
5. What is the sum of the first 50 terms of the sequence 3, 6, 9, 12,...?

**Tip**: You can use the same arithmetic series formula to sum consecutive numbers or any regularly spaced sequence.

What is the sum of all natural numbers from 1 to 40?

Learn how to calculate the sum of all natural numbers from 1 to 40 using the arithmetic series formula. This problem demonstrates key concepts in arithmetic series and is suitable for students in Grades 6-8. The total sum is 820.

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