Math Problem Statement

1 + 3 + 5 + ... + (2n - 3) + (2n - 1) = n^2

Solution

The equation shown in the image is:

1+3+5++(2n3)+(2n1)=n21 + 3 + 5 + \cdots + (2n - 3) + (2n - 1) = n^2

This is the sum of the first nn odd numbers. The series starts at 1 and goes up to (2n1)(2n - 1), and the sum of the first nn odd numbers is well-known to be equal to n2n^2.

Let's break this down:

  1. The sequence of odd numbers is: 1,3,5,7,,(2n1)1, 3, 5, 7, \dots, (2n - 1) The nn-th term of this sequence is 2n12n - 1.

  2. The sum of the first nn odd numbers can be written as: 1+3+5++(2n1)1 + 3 + 5 + \cdots + (2n - 1)

  3. There is a well-established result in mathematics that states: 1+3+5++(2n1)=n21 + 3 + 5 + \cdots + (2n - 1) = n^2

This result can be proved by induction or through other methods like visualizing the sum as the construction of a square of side length nn.

Would you like a detailed proof of this result, or any further explanation? Here are some related questions:

  1. How can this result be derived using induction?
  2. What is the significance of odd number sums in other areas of mathematics?
  3. Can we generalize this sum to other types of series, such as even numbers?
  4. How does this sum relate to the formula for the area of a square?
  5. What happens if we sum the squares of odd numbers instead?

Tip: The sum of consecutive odd numbers is one of the simplest examples of a series with a geometric visualization, making it useful for understanding number theory concepts.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Summation of Series

Formulas

Sum of first n odd numbers = n^2

Theorems

Sum of consecutive odd numbers theorem

Suitable Grade Level

Grades 8-10