Math Problem Statement

In an AP, the 16th term is three times the 5th term and the 12th term is 100. What is the sum of the first twenty terms?

Solution

The question in the image is as follows:

"In an AP (Arithmetic Progression), the 16th term is three times the 5th term, and the 12th term is 100.
What is the sum of the first twenty terms?"

Let's solve this step-by-step.

Step 1: Formula for the nth term of an AP

The nth term of an AP is given by:

Tn=a+(n1)dT_n = a + (n - 1) d

Where:

  • TnT_n is the nth term,
  • aa is the first term,
  • dd is the common difference, and
  • nn is the term number.

Step 2: Set up equations based on given conditions

  1. Condition 1: 16th term is three times the 5th term.

    • 16th term: T16=a+15dT_{16} = a + 15d
    • 5th term: T5=a+4dT_5 = a + 4d

    According to the condition: a+15d=3(a+4d)a + 15d = 3(a + 4d)

  2. Condition 2: The 12th term is 100.

    • 12th term: T12=a+11dT_{12} = a + 11d
    • According to the condition: a+11d=100a + 11d = 100

Step 3: Solve the system of equations

We now have two equations:

  1. a+15d=3(a+4d)a + 15d = 3(a + 4d)
  2. a+11d=100a + 11d = 100

Let's solve these equations.

  1. Simplify the first equation: a+15d=3a+12da + 15d = 3a + 12d 15d12d=3aa15d - 12d = 3a - a 3d=2a3d = 2a d=2a3d = \frac{2a}{3}

  2. Substitute d=2a3d = \frac{2a}{3} into the second equation: a+11×2a3=100a + 11 \times \frac{2a}{3} = 100 a+22a3=100a + \frac{22a}{3} = 100 3a+22a3=100\frac{3a + 22a}{3} = 100 25a3=100\frac{25a}{3} = 100 25a=30025a = 300 a=12a = 12

  3. Now substitute a=12a = 12 back into d=2a3d = \frac{2a}{3}: d=2×123=8d = \frac{2 \times 12}{3} = 8

Step 4: Find the sum of the first 20 terms

The sum of the first nn terms of an AP is given by:

Sn=n2×(2a+(n1)d)S_n = \frac{n}{2} \times (2a + (n - 1)d)

For n=20n = 20, a=12a = 12, and d=8d = 8:

S20=202×(2×12+(201)×8)S_{20} = \frac{20}{2} \times (2 \times 12 + (20 - 1) \times 8) S20=10×(24+19×8)S_{20} = 10 \times (24 + 19 \times 8) S20=10×(24+152)S_{20} = 10 \times (24 + 152) S20=10×176=1760S_{20} = 10 \times 176 = 1760

Final Answer:

The sum of the first twenty terms is 1760.

Would you like any further clarifications or details? Here are a few related questions you might want to explore:

  1. What is the general formula for the sum of an arithmetic progression?
  2. How do the common difference and first term affect the progression of terms in an AP?
  3. What is the significance of the 16th term in determining the behavior of the AP?
  4. Can we apply this method to find the sum of different numbers of terms?
  5. How does an arithmetic progression differ from a geometric progression?

Tip: Always remember that solving systems of equations is a powerful tool for determining unknowns in sequences!

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Math Problem Analysis

Mathematical Concepts

Arithmetic Progression (AP)
System of Equations
Sum of AP

Formulas

nth term of an AP: T_n = a + (n - 1)d
Sum of n terms of an AP: S_n = (n/2) * (2a + (n - 1)d)

Theorems

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Suitable Grade Level

Grades 10-12