At the farmers' market, Baldwin bought 3 1/5 pounds of string beans and 1 pound of lima beans. How many more pounds of string beans did Baldwin purchase?


To find out how many more pounds of string beans Baldwin purchased than lima beans, we subtract the weight of the lima beans from the weight of the string beans.

Baldwin bought:
- 3 1/5 pounds of string beans
- 1 pound of lima beans

First, convert 3 1/5 into an improper fraction or a decimal:
\[
3 \frac{1}{5} = 3 + \frac{1}{5} = \frac{15}{5} + \frac{1}{5} = \frac{16}{5} \text{ (as an improper fraction)}
\]
or as a decimal:
\[
3 \frac{1}{5} = 3.2
\]

Now, subtract the weight of the lima beans from the string beans:
\[
3.2 - 1 = 2.2 \text{ pounds}
\]

So, Baldwin purchased 2.2 more pounds of string beans than lima beans.

Would you like more details, or do you have any questions?

---

Here are 5 related questions:
1. How would the solution change if Baldwin had purchased 4 1/3 pounds of string beans?
2. Can you express the difference in weight as a fraction rather than a decimal?
3. What if Baldwin bought 2 pounds of lima beans instead of 1? How would that affect the result?
4. How can you convert between mixed numbers and improper fractions?
5. How would the calculation change if Baldwin bought half a pound of lima beans?

**Tip:** When working with mixed numbers, converting them to improper fractions or decimals often simplifies the calculations.

At the farmers' market, Baldwin bought 3 1/5 pounds of string beans and 1 pound of lima beans. How many more pounds of string beans did Baldwin purchase?

Learn how to calculate the difference in weight between string beans and lima beans in a real-life word problem. This exercise covers mixed number conversion and subtraction of decimals, making it ideal for Grades 4-6.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation