https://file.aiquickdraw.com/mathbot/file/1729999376646kmvgifm2.jpg

In this problem, we are given the expression:

\[
4 \frac{3}{5} - \frac{9}{10}
\]

Let's break down the solution in steps.

### Step 1: Convert the Mixed Number to an Improper Fraction

The mixed number \( 4 \frac{3}{5} \) can be converted to an improper fraction:

\[
4 \frac{3}{5} = \frac{4 \times 5 + 3}{5} = \frac{20 + 3}{5} = \frac{23}{5}
\]

### Step 2: Find a Common Denominator

To subtract \(\frac{23}{5}\) and \(\frac{9}{10}\), we need a common denominator. The least common multiple of 5 and 10 is 10. So, we convert \(\frac{23}{5}\) to a fraction with a denominator of 10:

\[
\frac{23}{5} = \frac{23 \times 2}{5 \times 2} = \frac{46}{10}
\]

### Step 3: Subtract the Fractions

Now, we can subtract \(\frac{46}{10} - \frac{9}{10}\):

\[
\frac{46}{10} - \frac{9}{10} = \frac{46 - 9}{10} = \frac{37}{10}
\]

### Step 4: Convert the Improper Fraction Back to a Mixed Number

\(\frac{37}{10}\) can be expressed as a mixed number:

\[
\frac{37}{10} = 3 \frac{7}{10}
\]

### Conclusion

The correct answer is:

\[
4 \frac{3}{5} - \frac{9}{10} = 3 \frac{7}{10}
\]

In the original solution shown in the image, it appears there was an error in converting or simplifying the fractions.

Would you like a more detailed breakdown or have any questions?

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### Practice Questions

1. How would you subtract \(5 \frac{2}{3} - \frac{7}{9}\)?
2. What is the least common multiple of 8 and 12?
3. How can you convert \(7 \frac{5}{6}\) into an improper fraction?
4. If you have \(\frac{5}{6} + \frac{4}{9}\), what is the result?
5. How do you simplify the fraction \(\frac{45}{60}\)?

### Tip

Always ensure to find the least common denominator when adding or subtracting fractions; this simplifies calculations and reduces errors.

Calculate 4 3/5 - 9/10 and identify the error in the solution.

Learn how to solve the subtraction of a mixed number and a fraction in the problem 4 3/5 - 9/10. This solution covers converting mixed numbers to improper fractions, finding a common denominator, and correctly simplifying the result. Ideal for Grade 6-8 students.

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