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The problem describes the motion of a submarine diving and then ascending to avoid an undersea cliff.

Here is the scenario:

- The submarine dives to a depth of **-972 feet**.
- It then ascends by **308 feet**.

To find the submarine's final depth after ascending, you can add the ascent (positive change) to the current depth (negative value).

\[
\text{Final depth} = -972 + 308
\]

Now, let's calculate:

\[
-972 + 308 = -664
\]

Thus, the submarine is at a depth of **-664 feet** after ascending to avoid the cliff.

Would you like further clarification or more details on the process?

Here are 5 related questions:
1. If the submarine ascended an additional 100 feet, where would it be?
2. How far below the surface would the submarine be after diving 200 more feet from its final position?
3. What if the submarine had ascended 350 feet instead of 308 feet?
4. Can you express the submarine’s depth change as a percentage?
5. How would the depth change if it ascended twice as much?

**Tip:** When dealing with problems involving changes in position or depth, always carefully track the signs of the values. Negative represents a decrease or downward movement, and positive represents an increase or upward movement.

A submarine is at the surface of the ocean, preparing to dive. It submerges and dives to -972 feet. Then, it ascends 308 feet to avoid hitting an undersea cliff. What integer represents the submarine's position in feet (depth) after it ascends to avoid the cliff?

Solve a submarine depth problem: A submarine dives to -972 feet and ascends 308 feet to avoid a cliff. Learn how to find its final depth using basic arithmetic, focusing on adding negative numbers. Suitable for students in Grades 6-8.

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