To calculate the stress on the wire, we use the following formula:

$\text{Stress} = \frac{F}{A}$

Where:

• $F$ = Force applied (in newtons, $N$)
• $A$ = Cross-sectional area of the wire (in square meters, $m^2$)

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Given data:

• $F = 524 \, N$
• Cross-sectional area $A = 0.08 \, \text{cm}^2$

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Step 1: Convert the cross-sectional area from cm² to m²

$1 \, \text{cm}^2 = 10^{-4} \, \text{m}^2$
Therefore: $A = 0.08 \, \text{cm}^2 = 0.08 \times 10^{-4} \, \text{m}^2 = 8.0 \times 10^{-6} \, \text{m}^2$

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Step 2: Calculate the stress

Substitute the values into the formula:

$\text{Stress} = \frac{524 \, N}{8.0 \times 10^{-6} \, \text{m}^2}$

$\text{Stress} = 6.55 \times 10^7 \, \text{N/m}^2$

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Final Answer:

The stress on the wire is:

$\boxed{6.55 \times 10^7 \, \text{N/m}^2}$

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Would you like a detailed breakdown of strain and Young's modulus as well? 😊

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Here are 5 related questions to try next:

1. How do you calculate strain in a stretched wire?
2. What is Young's modulus, and how is it related to stress and strain?
3. How would the stress change if the cross-sectional area doubled?
4. What happens to the length if the applied force is reduced?
5. How do you calculate elastic potential energy stored in a stretched wire?

Tip: Always double-check unit conversions to avoid errors in calculations! 😊