
Salary
98837
57380
100702
272500
90090
74235
65270
73877
66346
109739
52718
58456
76029
75311
108448
64553


a) For the data shown above, find the following.

    Round the answer in the first blank to 1 decimal place(s).

    In the second blank put the correct units.

    Find the mean: 
 


    Find the median: 
 


    Find the range: 
 


    Find the standard deviation: 
 

Here are the results for the given salary dataHere are the results for the given salary 

- **Mean**: 90280.7 (rounded to 1 decimal place)
- **Median**: 74773
- **Range**: 219782
- **Standard Deviation**: 51906.8 (rounded to 1 decimal place)

Would you like further clarification on any of these results or more details on how they were calculated?

Here are some additional questions that you may find useful:

1. How would the mean change if the highest salary were excluded?
2. What is the difference between sample and population standard deviation?
3. How does the range affect the overall data spread?
4. What can be inferred from the large standard deviation in this dataset?
5. What is the interquartile range for this data?

**Tip**: The standard deviation gives insight into how much variation exists from the mean. The larger the standard deviation, the more spread out the data is.

For the given salary 98837, 57380, 100702, 272500, 90090, 74235, 65270, 73877, 66346, 109739, 52718, 58456, 76029, 75311, 108448, 64553. Find the mean, median, range, and standard deviation. Round to 1 decimal place and include units.

Analyze salary data and calculate the mean (90280.7), median (74773), range (219782), and standard deviation (51906.8). Understand key statistical concepts such as central tendency and dispersion. Suitable for students in Grades 10-12.

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