The expression you've written is $(2 + 3i)^2$, where $i$ represents the imaginary unit, defined by $i^2 = -1$.

To solve this, let's use the formula for expanding a binomial $(a + b)^2 = a^2 + 2ab + b^2$.

Here, $a = 2$ and $b = 3i$:

$(2 + 3i)^2 = 2^2 + 2(2)(3i) + (3i)^2$

Now, let's simplify each part:

$2^2 = 4$ $2(2)(3i) = 12i$ $(3i)^2 = 9i^2 = 9(-1) = -9$

Now, combine everything:

$4 + 12i - 9 = -5 + 12i$

So, $(2 + 3i)^2 = -5 + 12i$.

---

Do you want more details or have any questions?

Here are some related questions you might find interesting:

1. What is the general form of the square of any complex number $(a + bi)^2$?
2. How can complex numbers be represented on the Argand plane?
3. What is the geometric meaning of squaring a complex number?
4. How do you multiply two complex numbers?
5. What is the modulus of $2 + 3i$?

Tip: When squaring complex numbers, always remember that $i^2 = -1$ to handle the imaginary unit correctly.