The intensity of a sound in decibels is given by the equation:

$I(\text{dB}) = 10 \log\left(\frac{I}{I_0}\right)$

where:

• $I$ is the sound intensity in $\text{W/m}^2$,
• $I_0 = 10^{-12} \, \text{W/m}^2$ is the reference sound intensity.

To find the intensity $I$ from the decibel value $I(\text{dB})$, we can rearrange the formula as follows:

1. Start with the given equation: $I(\text{dB}) = 10 \log\left(\frac{I}{I_0}\right)$
2. Divide both sides by 10: $\frac{I(\text{dB})}{10} = \log\left(\frac{I}{I_0}\right)$
3. Convert the logarithmic equation to its exponential form: $\frac{I}{I_0} = 10^{\frac{I(\text{dB})}{10}}$
4. Multiply both sides by $I_0$ to isolate $I$: $I = I_0 \cdot 10^{\frac{I(\text{dB})}{10}}$

Now, substitute $I_0 = 10^{-12} \, \text{W/m}^2$ and the given decibel value for the washing machine (let's call this value $I(\text{dB})$):

$I = 10^{-12} \cdot 10^{\frac{I(\text{dB})}{10}}$

Please provide the value of $I(\text{dB})$ so I can calculate the intensity in $\text{W/m}^2$.