Math Problem Statement

Solve

The diagram shows ABC and PCD are right-angled triangles. Angle ABC = 40°, AB = 10 cm, PD = 8 cm, and BD = 15 cm. Calculate, giving your answers correct to 1 decimal place: i) The length of BC in centimeters, ii) The size of angle PDC in degrees.

Solution

Let's break down the problem and solve it step by step.

Given:

  • ABC\triangle ABC and PCD\triangle PCD are right-angled triangles.
  • Angle ABC=40\angle ABC = 40^\circ
  • AB=10AB = 10 cm, PD=8PD = 8 cm, BD=15BD = 15 cm.

We need to calculate:

  1. The length of BCBC in centimeters.
  2. The size of angle PDCPDC in degrees.

i) Finding the length of BCBC:

Using right-angled triangle ABCABC, we can apply trigonometric ratios. Since we know the angle ABC=40\angle ABC = 40^\circ, and we are given the adjacent side AB=10cmAB = 10 \, \text{cm}, we will use the tangent ratio:

tan(θ)=oppositeadjacent\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}

Here:

  • Opposite side is BCBC,
  • Adjacent side is AB=10cmAB = 10 \, \text{cm},
  • θ=40\theta = 40^\circ.

tan(40)=BC10\tan(40^\circ) = \frac{BC}{10}

Thus, solving for BCBC:

BC=10×tan(40)BC = 10 \times \tan(40^\circ)

Using a calculator:

BC10×0.83918.39cmBC \approx 10 \times 0.8391 \approx 8.39 \, \text{cm}

So, the length of BCBC is approximately 8.4 cm (to 1 decimal place).


ii) Finding the size of angle PDCPDC:

We now look at triangle PCDPCD. We know that:

  • PD=8cmPD = 8 \, \text{cm},
  • BD=15cmBD = 15 \, \text{cm}, so CD=BDBC=158.396.61cm.CD = BD - BC = 15 - 8.39 \approx 6.61 \, \text{cm}.

Now, we can use the tangent ratio in triangle PCDPCD to find PDC\angle PDC:

tan(PDC)=PCCD\tan(\angle PDC) = \frac{PC}{CD}

Since PC=PD=8cmPC = PD = 8 \, \text{cm} and CD6.61cmCD \approx 6.61 \, \text{cm}, we have:

tan(PDC)=86.611.210\tan(\angle PDC) = \frac{8}{6.61} \approx 1.210

Taking the inverse tangent (arctan) to find the angle:

PDC=tan1(1.210)50.2\angle PDC = \tan^{-1}(1.210) \approx 50.2^\circ

Thus, the size of angle PDCPDC is approximately 50.2 degrees.


Summary:

  1. The length of BCBC is approximately 8.4 cm.
  2. The size of angle PDCPDC is approximately 50.2 degrees.

Would you like a more detailed explanation for any part of the solution?
Here are five questions to further explore this topic:

  1. How would the calculations change if the angle ABC\angle ABC was different?
  2. Can you explain how the tangent ratio is used to solve for sides and angles?
  3. What is the difference between the sine, cosine, and tangent ratios in trigonometry?
  4. How would you solve for unknown sides using the Pythagorean theorem?
  5. How do inverse trigonometric functions help in finding angles?

Tip: Always ensure your calculator is set to the correct mode (degrees or radians) based on the angle unit you're working with.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Right-angled triangles
Tangent ratio

Formulas

tan(θ) = opposite/adjacent
tan(θ) = PC/CD
CD = BD - BC

Theorems

Trigonometric ratios in right-angled triangles

Suitable Grade Level

Grades 9-11