Math Problem Statement

show steps to solve this. Does the system of equations have no solution, one solution, or an infinite number of solutions?

y=−4x+9y y=2/3x−5

Solution

Let's solve the system of equations and analyze its solutions.

The given system is:

  1. y=4x+9yy = -4x + 9y
  2. y=23x5y = \frac{2}{3}x - 5

Step 1: Simplify the first equation

Start by simplifying the first equation:
y=4x+9yy = -4x + 9y Subtract 9y9y from both sides: y9y=4xy - 9y = -4x 8y=4x-8y = -4x Now, divide both sides by 8-8: y=12xy = \frac{1}{2}x

So the first equation simplifies to: y=12xy = \frac{1}{2}x

Step 2: Set the two equations equal

Now that we have the simplified form of the first equation y=12xy = \frac{1}{2}x and the second equation y=23x5y = \frac{2}{3}x - 5, we can set them equal to each other to solve for xx.

12x=23x5\frac{1}{2}x = \frac{2}{3}x - 5

Step 3: Solve for xx

To eliminate the fractions, multiply through by 6 (the least common denominator of 2 and 3): 6×12x=6×(23x5)6 \times \frac{1}{2}x = 6 \times \left( \frac{2}{3}x - 5 \right) This simplifies to: 3x=4x303x = 4x - 30 Now, subtract 4x4x from both sides: 3x4x=303x - 4x = -30 x=30-x = -30 Multiply both sides by 1-1: x=30x = 30

Step 4: Solve for yy

Now substitute x=30x = 30 into either of the original equations to solve for yy. Let's use the second equation: y=23x5y = \frac{2}{3}x - 5 Substitute x=30x = 30: y=23(30)5y = \frac{2}{3}(30) - 5 y=205=15y = 20 - 5 = 15

Step 5: Conclusion

The solution to the system of equations is x=30x = 30 and y=15y = 15, which means the system has one solution.

Final Answer:

The system of equations has one solution, which is x=30x = 30 and y=15y = 15.


Would you like further explanation on any step, or do you have any additional questions?

Here are some related questions you can explore:

  1. What happens if the coefficients of xx in both equations are the same?
  2. How would you handle a system of equations with no solution?
  3. What if the equations were both in standard form, Ax+By=CAx + By = C?
  4. How do you solve a system of equations using substitution?
  5. How would the solution change if one of the equations was nonlinear?

Tip: When dealing with a system of linear equations, always simplify the equations first and check for possible points of intersection graphically for a better understanding of the solution!

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Math Problem Analysis

Mathematical Concepts

Systems of Equations
Algebra
Linear Equations

Formulas

y = mx + b
System of equations substitution method

Theorems

Linear system solution
Elimination method
Substitution method

Suitable Grade Level

Grades 7-9