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We can solve this system of equations using algebra. The problem provides two different transactions involving the purchase of bags of chocolate kisses and packages of gummi bears.

Let:
- $ x $ be the cost of one bag of chocolate kisses.
- $ y $ be the cost of one package of gummi bears.

From the information in the image, we can set up two equations:

1. The first sugar addict paid $40.25 for 4 bags of chocolate kisses and 5 packages of gummi bears:
\[
4x + 5y = 40.25
\]

2. The second sugar addict paid $21 for 3 bags of chocolate kisses and 2 packages of gummi bears:
\[
3x + 2y = 21
\]

We will solve this system of equations to find $ x $ (the cost of each bag of chocolate kisses) and $ y $ (the cost of each package of gummi bears). Let's proceed with solving the system.The solution to the system of equations is:

- Each bag of chocolate kisses costs **$3.50**.
- Each package of gummi bears costs **$5.25**.

Would you like more details on how these values were calculated, or do you have any other questions?

Here are 5 related questions to expand your understanding:
1. How would the cost change if Sugar Addict #1 bought 6 bags of chocolate kisses instead?
2. How can you verify these results using substitution?
3. What if Sugar Addict #2 had bought only 1 package of gummi bears, how would the equations change?
4. Can you represent this system of equations graphically?
5. How would the total cost change if the prices of gummi bears increased by 10%?

**Tip**: Systems of equations are often solved using substitution or elimination methods. Both approaches are effective depending on the complexity of the equations.

Sugar Addict #1 paid $40.25 for 4 bags of chocolate kisses and 5 packages of gummi bears. Sugar Addict #2 paid $21 for 3 bags of chocolate kisses and 2 packages of gummi bears. a) How much did each bag of chocolate kisses cost? b) How much did each package of gummi bears cost?

Learn how to solve a real-world problem involving systems of equations to find the cost of chocolate kisses and gummi bears. This example shows how to set up and solve linear equations using substitution or elimination methods. Suitable for students in Grades 8-10.

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