Math Problem Statement

III. Slove the following septum of brail equation by eliminating method

  1. 4x + 3y = 12 x + 3y = 25

  2. x + y = 7 x - y = 5

Solution

Let's solve the given systems of equations using the elimination method.


Problem 1:

We are given the system:

  1. 4x+3y=124x + 3y = 12
  2. x+3y=25x + 3y = 25

Step 1: Eliminate yy

We can eliminate yy by aligning the coefficients of yy in both equations. The second equation already has 3y3y, and the first equation also has 3y3y, so we can subtract one equation from the other to eliminate yy.

We'll subtract equation (2) from equation (1):

(4x+3y)(x+3y)=1225(4x + 3y) - (x + 3y) = 12 - 25

Simplifying:

4x+3yx3y=134x + 3y - x - 3y = -13 3x=133x = -13

Solving for xx:

x=133x = \frac{-13}{3}

Step 2: Substitute x=133x = \frac{-13}{3} into one of the original equations.

Substitute x=133x = \frac{-13}{3} into the second equation x+3y=25x + 3y = 25:

133+3y=25\frac{-13}{3} + 3y = 25

To simplify this, first multiply the entire equation by 3 to eliminate the fraction:

13+9y=75-13 + 9y = 75

Solve for yy:

9y=75+139y = 75 + 13 9y=889y = 88 y=889y = \frac{88}{9}


Problem 2:

We are given the system:

  1. x+y=7x + y = 7
  2. xy=5x - y = 5

Step 1: Eliminate yy

We can eliminate yy by adding both equations:

(x+y)+(xy)=7+5(x + y) + (x - y) = 7 + 5

Simplifying:

x+y+xy=12x + y + x - y = 12 2x=122x = 12

Solving for xx:

x=122=6x = \frac{12}{2} = 6

Step 2: Substitute x=6x = 6 into one of the original equations.

Substitute x=6x = 6 into the first equation x+y=7x + y = 7:

6+y=76 + y = 7

Solve for yy:

y=76=1y = 7 - 6 = 1


Final Solutions:

  1. For the system 4x+3y=124x + 3y = 12 and x+3y=25x + 3y = 25, the solution is: x=133,y=889x = \frac{-13}{3}, \quad y = \frac{88}{9}

  2. For the system x+y=7x + y = 7 and xy=5x - y = 5, the solution is: x=6,y=1x = 6, \quad y = 1


Would you like more details or have any questions about the steps? Here are some related questions for you:

  1. How would the elimination method differ if we had different coefficients for yy in the two equations?
  2. Can the substitution method be used instead of elimination in these systems? How?
  3. What happens if one of the equations in a system is inconsistent (e.g., 2x+3y=102x + 3y = 10 and 2x+3y=152x + 3y = 15)?
  4. How can the elimination method be applied to systems of three equations?
  5. What if we had the system with fractional coefficients, how would the process change?

Tip: When using the elimination method, always try to align the coefficients of one variable first. This will make the elimination process smoother and quicker.

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Math Problem Analysis

Mathematical Concepts

Algebra
Systems of Linear Equations
Elimination Method

Formulas

Elimination method for systems of linear equations

Theorems

Elimination theorem

Suitable Grade Level

Grades 7-9