Let's solve this system of three equations using either substitution or elimination.

The given system of equations is:

1. $3x + 2y - z = 11$
2. $x + 3y + z = 16$
3. $2x - 2y + z = 9$

Step 1: Add Equation 2 and Equation 3 to eliminate $z$.

Adding these two equations cancels out $z$:

$(x + 3y + z) + (2x - 2y + z) = 16 + 9$ $x + 2x + 3y - 2y + z + z = 25$ $3x + y + 2z = 25$

Step 2: Solve for one variable

You can solve the system using any preferred method!