We have the following system of linear equations:

1. \(-1 = 2x - y\) 
2. \(8x - 4y = -4\)

### Step 1: Solve for one variable
Let's solve the first equation for \(y\):

\[
-1 = 2x - y
\]

Rearrange to get \(y\) in terms of \(x\):

\[
y = 2x + 1
\]

### Step 2: Substitute into the second equation
Now substitute \(y = 2x + 1\) into the second equation:

\[
8x - 4(2x + 1) = -4
\]

Expand the equation:

\[
8x - 8x - 4 = -4
\]

Simplify:

\[
-4 = -4
\]

This is a true statement, which means the system has **infinitely many solutions**. The two equations are dependent, meaning they represent the same line.

Thus, the solution is not a single point, but rather all points \((x, y)\) that satisfy the equation \(y = 2x + 1\).

### Solution:
\[
y = 2x + 1
\]

Any point on this line is a solution to the system.

Would you like to explore this solution further?

### Related Questions:
1. What is a dependent system of linear equations?
2. How do we solve a system of equations using substitution?
3. What are the different methods to solve a system of linear equations?
4. Can a system have no solution or a unique solution? Under what conditions?
5. How do graphing methods help visualize solutions to systems of equations?

**Tip**: When solving a system of equations, always check if the equations are multiples of each other to identify dependent systems.

Learn how to solve the system of linear equations -1 = 2x - y and 8x - 4y = -4 using the substitution method. This problem demonstrates the concept of dependent systems, where equations represent the same line, leading to infinitely many solutions. Ideal for students in Grades 8-10.

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