Let's solve the given system of equations:

1. $2x + 3y = 6$
2. $x = 3$

Since the value of $x$ is already given as $3$, we can substitute $x = 3$ into the first equation.

Substitute into $2x + 3y = 6$:

$2(3) + 3y = 6$

This simplifies to:

$6 + 3y = 6$

Now, subtract 6 from both sides:

$3y = 0$

Finally, divide both sides by 3:

$y = 0$

Thus, the solution to the system is:

$x = 3 \quad \text{and} \quad y = 0$

If you have any further questions or would like more details on the solution process, feel free to ask!

Here are some related questions you may find useful:

1. What are the different methods to solve a system of linear equations (e.g., substitution, elimination)?
2. How do you solve systems of equations with two variables using matrices?
3. How can you graphically represent the solution to a system of linear equations?
4. What is the significance of parallel lines in a system of equations?
5. How do you solve systems of equations with three variables?

Tip: When substituting into equations, always double-check the values to avoid calculation errors!