Math Problem Statement

x^2 - y^2 = 24, xy = 35, find x + y.

Solution

We are given the following system of equations:

x2y2=24x^2 - y^2 = 24 xy=35xy = 35 x+y=?x + y = ?

Step 1: Factor the first equation

We can rewrite the first equation using the difference of squares:

x2y2=(xy)(x+y)x^2 - y^2 = (x - y)(x + y)

Thus, the equation becomes:

(xy)(x+y)=24(x - y)(x + y) = 24

Step 2: Let s=x+ys = x + y and p=xyp = x - y

Now the equation becomes:

ps=24p \cdot s = 24

And we also have:

xy=35xy = 35

At this point, we have two new equations:

ps=24(1)ps = 24 \quad \text{(1)} xy=35(2)xy = 35 \quad \text{(2)}

Step 3: Solve the system of equations

We will solve this system by finding x+yx + y. Using a substitution method for x+y=sx + y = s, let's first check if there are any specific values for ss.

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Math Problem Analysis

Mathematical Concepts

Algebra
Systems of Equations
Difference of Squares

Formulas

Difference of Squares: x^2 - y^2 = (x - y)(x + y)
Product and Sum Relationships in Quadratic Equations

Theorems

Difference of Squares Theorem

Suitable Grade Level

Grades 9-12