Math Problem Statement

FINAL TERM ACTIVITY 1.pdf

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Answer this 2 problem

Solution

Problem 1: Largest vertical load PP at CC

To solve this, we need to consider:

  1. Stress in the steel rod at BB: Stress=ForceArea40ksi\text{Stress} = \frac{\text{Force}}{\text{Area}} \leq 40 \, \text{ksi}

  2. Vertical movement limitation at CC: ΔC=PLAE0.15in\Delta_C = \frac{PL}{AE} \leq 0.15 \, \text{in} Where:

    • PP: Load applied
    • LL: Length of the steel rod
    • AA: Cross-sectional area of the rod
    • EE: Young's modulus for steel

By combining these constraints and any equilibrium conditions provided by the geometry of the system (e.g., lever arm moments), we can solve for PP.


Problem 2: Change in length of the steel shaft ABCDABCD

The formula for axial deformation under axial load is: Δ=PiLiAiE\Delta = \sum \frac{P_i L_i}{A_i E} Where:

  • PiP_i: Axial load on segment ii
  • LiL_i: Length of segment ii
  • AiA_i: Cross-sectional area of segment ii
  • EE: Young's modulus for steel

Steps:

  1. Break the shaft ABCDABCD into segments based on where the loads are applied.
  2. Calculate the deformation for each segment separately.
  3. Sum the deformations to find the total change in length.

To solve both problems completely, I need details such as:

  • Lengths, areas, and geometric properties of the members.
  • Specific axial loads and their application points.
  • Any additional constraints or dimensions.

Would you like me to assume reasonable values or provide a detailed example?

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Math Problem Analysis

Mathematical Concepts

Statics
Mechanics of Materials
Stress-Strain Analysis
Axial Deformation

Formulas

Stress = Force / Area ≤ 40 ksi
Vertical deformation Δ = PL / AE ≤ 0.15 in
Axial deformation formula: Δ = Σ (P_i * L_i) / (A_i * E)

Theorems

Hooke's Law for linear elastic materials
Principle of superposition for axial deformations

Suitable Grade Level

Undergraduate Engineering