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The question in the image asks to split the number 247 into two parts such that when the first part is divided by 5 and the second part is divided by 8, the resulting quotients are equal. Here's a breakdown of how to approach this:

1. Let the two numbers be \( x \) and \( 247 - x \).
   
2. The first number is \( x \), and the condition says that when divided by 5, the quotient should be the same as when the second number, \( 247 - x \), is divided by 8. Mathematically, this can be expressed as:
   \[
   \frac{x}{5} = \frac{247 - x}{8}
   \]

3. To solve this equation, cross-multiply to get rid of the fractions:
   \[
   8x = 5(247 - x)
   \]

4. Expand and simplify the equation:
   \[
   8x = 1235 - 5x
   \]
   \[
   8x + 5x = 1235
   \]
   \[
   13x = 1235
   \]

5. Solve for \( x \):
   \[
   x = \frac{1235}{13} = 95
   \]

6. Therefore, the first number is \( x = 95 \), and the second number is \( 247 - 95 = 152 \).

### Final Answer:
- The two numbers are 95 and 152.

Would you like more details, or do you have any questions?

### Related Questions:
1. How can we verify the solution by plugging the numbers back into the equation?
2. What happens if the sum is a different number instead of 247?
3. How does this technique apply to other ratios, like \( \frac{x}{3} = \frac{y}{7} \)?
4. Can this method be used if fractions are involved instead of integers?
5. What if both parts have to satisfy more conditions, like a common divisor?

### Tip:
Always check your final solution by substituting the values back into the original equation to ensure it satisfies the conditions.

247 ədədini elə iki ədədin cəmi şəklində göstərin ki, birinci ədədi 5-ə, ikinci ədədi isə 8-ə böldükdə, alınan qismətlər bərabər olsun

This problem demonstrates how to split the number 247 into two numbers such that the first number divided by 5 and the second number divided by 8 yield equal quotients. Learn the step-by-step algebraic solution suitable for students in Grades 7-9.

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