Math Problem Statement

sin(cos−1(square root2/2+ tan−1(square root3))

Solution

Let's break down the expression step by step.

The given expression is:

sin(cos1(22+tan1(3)))\sin \left( \cos^{-1} \left( \frac{\sqrt{2}}{2} + \tan^{-1} \left( \sqrt{3} \right) \right) \right)

Step 1: Understand the components

  1. tan1(3)\tan^{-1} \left( \sqrt{3} \right):

    • The value tan1(3)\tan^{-1} \left( \sqrt{3} \right) refers to the angle whose tangent is 3\sqrt{3}. This corresponds to an angle of π3\frac{\pi}{3} radians (since tanπ3=3\tan \frac{\pi}{3} = \sqrt{3}).
  2. 22+tan1(3)\frac{\sqrt{2}}{2} + \tan^{-1} \left( \sqrt{3} \right):

    • We know tan1(3)=π3\tan^{-1} \left( \sqrt{3} \right) = \frac{\pi}{3}, so we need to add 22\frac{\sqrt{2}}{2} to π3\frac{\pi}{3}. The sum is just a number, so we now have: 22+π3\frac{\sqrt{2}}{2} + \frac{\pi}{3}

Step 2: Evaluate cos1(22+π3)\cos^{-1} \left( \frac{\sqrt{2}}{2} + \frac{\pi}{3} \right)

  • The expression now becomes: cos1(22+π3)\cos^{-1} \left( \frac{\sqrt{2}}{2} + \frac{\pi}{3} \right)

    At this stage, it's important to note that 22\frac{\sqrt{2}}{2} is a number approximately equal to 0.7071, and adding π3\frac{\pi}{3} (about 1.047) gives us a sum that exceeds the allowable domain for cos1\cos^{-1}, which only accepts values in the range [1,1][-1, 1].

Thus, the expression inside the cos1\cos^{-1} function is not valid, as the sum 22+π3>1\frac{\sqrt{2}}{2} + \frac{\pi}{3} > 1.

Conclusion:

The expression as written does not have a valid mathematical solution due to the invalid domain for the inverse cosine function.

Would you like help with another problem or need clarification on any step?

Related Questions:

  1. How do inverse trigonometric functions work with sums inside them?
  2. What are the domains of inverse trigonometric functions like sin1\sin^{-1}, cos1\cos^{-1}, and tan1\tan^{-1}?
  3. How do you simplify trigonometric expressions with combined inverse functions?
  4. What is the range of cos1\cos^{-1} and how does it affect solutions?
  5. What happens when the argument of an inverse trigonometric function is outside its domain?

Tip: Always check the range and domain of inverse functions to ensure the argument is valid before attempting to simplify or calculate values.

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Math Problem Analysis

Mathematical Concepts

Inverse Trigonometric Functions
Trigonometric Identities
Domain of Functions

Formulas

sin(θ)
cos⁻¹(x)
tan⁻¹(x)

Theorems

Domain of inverse trigonometric functions
Range of inverse cosine

Suitable Grade Level

Grades 11-12