Simplify the above equation and solve for
n(S ∩ B).
613	 =
− n(S ∩ B)

= 	−n(S ∩ B)

= 	n(S ∩ B)

Let's simplify the given equations step by step:

1. The original equation is:
   \[
   613 = -n(S \cap B)
   \]
   
2. To isolate \( n(S \cap B) \), we can multiply both sides by \( -1 \) to get rid of the negative sign:
   \[
   -613 = n(S \cap B)
   \]

Thus, the solution is:
\[
n(S \cap B) = -613
\]

Would you like further details or explanations?

Here are five related questions to deepen your understanding:
1. What does \( n(S \cap B) \) represent in set theory?
2. How can we interpret a negative value for the cardinality \( n(S \cap B) \)?
3. What are some common operations in set theory, like union and intersection?
4. How would this equation change if you had \( n(S \cup B) \) instead?
5. Can cardinality \( n(A \cap B) \) ever be negative in real-life contexts?

**Tip:** Always check if the operation you're performing on an equation is valid in the context of the problem, especially in set theory.

Simplify the above equation and solve for n(S ∩ B). 613 = −n(S ∩ B)

Learn how to solve the equation 613 = −n(S ∩ B) by simplifying and isolating the intersection of sets. This problem involves key set theory and algebra concepts, such as the intersection of sets and cardinality. Suitable for students in Grades 8-10.

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