Math Problem Statement
x^2y''+3xy'+y=0, y=x^-1
Solution
You are dealing with a second-order linear differential equation:
The function is proposed as a solution, so we need to check whether this satisfies the equation.
Step-by-Step Verification:
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Find and for :
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Substitute , , and into the given equation:
Substituting the values of , , and :
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Simplify each term:
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Combine all terms:
The equation simplifies to , which is true.
Conclusion:
The function satisfies the given differential equation.
Would you like more details or have any questions?
Here are 5 related questions to deepen your understanding:
- What is the general solution to a second-order linear differential equation?
- Can this equation have other solutions besides ?
- How would the solution change if there was a non-homogeneous term (e.g., )?
- How do you solve second-order differential equations using the method of undetermined coefficients?
- How would you apply variation of parameters to solve such equations?
Tip: For verifying solutions to differential equations, always compute the derivatives carefully and substitute them back into the original equation for simplification.
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Math Problem Analysis
Mathematical Concepts
Differential Equations
Second-Order Linear Differential Equations
Homogeneous Equations
Verification of Solutions
Formulas
x^2 y'' + 3xy' + y = 0
y = x^{-1}
y' = -x^{-2}
y'' = 2x^{-3}
Theorems
Theory of Linear Homogeneous Differential Equations
Solution Verification for Differential Equations
Suitable Grade Level
Undergraduate - Calculus II or Differential Equations
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