Math Problem Statement

Solve: \( \frac{4}{x - 4} + \frac{2}{x + 1} = \frac{5x}{x^2 - 3x - 4} \). If no solution exists, state this.

Solution

To solve the equation:

4x4+2x+1=5xx23x4\frac{4}{x - 4} + \frac{2}{x + 1} = \frac{5x}{x^2 - 3x - 4}

Step 1: Factor the Denominator on the Right Side

The denominator on the right side is x23x4x^2 - 3x - 4. We can factor this as: x23x4=(x4)(x+1)x^2 - 3x - 4 = (x - 4)(x + 1)

So, the equation becomes: 4x4+2x+1=5x(x4)(x+1)\frac{4}{x - 4} + \frac{2}{x + 1} = \frac{5x}{(x - 4)(x + 1)}

Step 2: Find a Common Denominator

The common denominator for all terms is (x4)(x+1)(x - 4)(x + 1). Rewrite each term with this denominator: 4(x+1)(x4)(x+1)+2(x4)(x4)(x+1)=5x(x4)(x+1)\frac{4(x + 1)}{(x - 4)(x + 1)} + \frac{2(x - 4)}{(x - 4)(x + 1)} = \frac{5x}{(x - 4)(x + 1)}

Step 3: Expand and Combine Terms in the Numerator

Expanding each term in the numerator:

  1. 4(x+1)=4x+44(x + 1) = 4x + 4
  2. 2(x4)=2x82(x - 4) = 2x - 8

So, the equation becomes: 4x+4+2x8(x4)(x+1)=5x(x4)(x+1)\frac{4x + 4 + 2x - 8}{(x - 4)(x + 1)} = \frac{5x}{(x - 4)(x + 1)}

Combine like terms in the numerator: [ \frac{(

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Math Problem Analysis

Mathematical Concepts

Algebra
Rational Expressions
Factoring

Formulas

\( a^2 - b^2 = (a - b)(a + b) \) for factoring quadratics

Theorems

Properties of Equality
Factoring of Quadratics

Suitable Grade Level

Grades 9-10