Math Problem Statement

Solve for x: x-1x+3>0 inquality with rational expression and interval, test points graphics

Solution

Let's solve the inequality x1x+3>0\frac{x - 1}{x + 3} > 0.

Step-by-Step Solution:

  1. Find Critical Points: First, we need to find the points where the expression is either zero or undefined.

    • The numerator x1=0x - 1 = 0 when x=1x = 1.
    • The denominator x+3=0x + 3 = 0 when x=3x = -3 (this makes the expression undefined).

    So, the critical points are x=1x = 1 (where the expression is zero) and x=3x = -3 (where the expression is undefined).

  2. Divide the Number Line into Intervals: Based on the critical points x=1x = 1 and x=3x = -3, divide the number line into the following intervals:

    • (,3)(-\infty, -3)
    • (3,1)(-3, 1)
    • (1,)(1, \infty)
  3. Test Each Interval: Choose a test point in each interval and check the sign of the rational expression x1x+3\frac{x - 1}{x + 3} in that interval.

    • For (,3)(-\infty, -3), choose x=4x = -4: 414+3=51=5(positive)\frac{-4 - 1}{-4 + 3} = \frac{-5}{-1} = 5 \quad (\text{positive})

    • For (3,1)(-3, 1), choose x=0x = 0: 010+3=13(negative)\frac{0 - 1}{0 + 3} = \frac{-1}{3} \quad (\text{negative})

    • For (1,)(1, \infty), choose x=2x = 2: 212+3=15(positive)\frac{2 - 1}{2 + 3} = \frac{1}{5} \quad (\text{positive})

  4. Determine the Solution: The expression x1x+3\frac{x - 1}{x + 3} is positive in the intervals (,3)(-\infty, -3) and (1,)(1, \infty).

    • At x=3x = -3, the expression is undefined, so we exclude x=3x = -3.
    • At x=1x = 1, the expression equals zero, but we want x1x+3>0\frac{x - 1}{x + 3} > 0, so exclude x=1x = 1.

    Therefore, the solution to the inequality is: x(,3)(1,)x \in (-\infty, -3) \cup (1, \infty)

Graphing the Solution:

To graph the solution:

  • Draw a number line with the critical points x=3x = -3 and x=1x = 1 marked.
  • Use open circles at x=3x = -3 and x=1x = 1 to show these points are excluded from the solution.
  • Shade the intervals (,3)(-\infty, -3) and (1,)(1, \infty).

Conclusion:

The solution to x1x+3>0\frac{x - 1}{x + 3} > 0 is x(,3)(1,)x \in (-\infty, -3) \cup (1, \infty).

Would you like the graph, or do you have questions?


5 Related Questions:

  1. How do we solve inequalities involving polynomials?
  2. What happens if the inequality were x1x+30\frac{x - 1}{x + 3} \geq 0?
  3. Can you explain how to solve absolute value inequalities?
  4. How can we solve inequalities with quadratic expressions?
  5. What are the key differences between solving linear equations and inequalities?

Tip:

When solving inequalities with rational expressions, always remember to check where the denominator is zero and test the intervals accordingly.

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Math Problem Analysis

Mathematical Concepts

Inequalities
Rational Expressions
Number Line Intervals

Formulas

Critical points in rational expressions
Sign testing in intervals

Theorems

Zero Product Property
Sign Analysis of Rational Expressions

Suitable Grade Level

Grades 9-11